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a = (1/y) is the only real number solution. I believe y=63, so 1/63
Using the units digit of the decimal equivalent of today’s date in binary as y; which real numbers, a, does the following equation have a unique solution?
a yx + y-x = y
a*3 = 1
so a = 1/3
a = (1/3)
a = 1/3
Posted before completing,
equation becomes, (ay-1)x=0
solving, equation will have a unique solution for all real numbers where a IS NOT EQUAL to 1.
All numbers except 1/3.
Today’s (yesterday's) date is 11/11/11, which is 00111111b as binary.
This equivalent of 0x3F hexadecimal and 63 decimal.
Therefore, digits of value of 63 are 6 and 3.
So, the finally equation is:
a 63 + 6 - 3 = 6 (or 63a + 6 - 3 = 6)
And it has unique solution:
a = 3/63, which is finally:
a = 1/21
a=1/63... ( x(63a-1)=0 since 0b111111 = 63)
Decimal equivalent of the date "11/11/11" = 63
Units digit of 63 = 3
3x + 3-x = y
Solution: x = 0
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