# Answer Question #5 - E2E Challenge

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### Answer Question #5 - E2E Challenge

(don't worry your answer won't show until after the contest is over!)

If you have no idea what I'm talking about check out the rules to play here!

• Absolute Accuracy = (Input Voltage x % of Reading)

Accuracy = .025 ?

• But that just doesn't seem right...

• Maybe 1 / 20log(2) - (base 10) ?

• 97.5%

• You are designing a data acquisition system where the tester’s power supply is not accurately calibrated. The specification of the tester indicates it has a rejection ratio of 2%/Volt. Your analysis shows five codes were incorrect. What is the accuracy of your system?

i think something is missing in the question , but it should be (5 codes out of how many sent) give the accuracy then also need to know what voltage the system is running at.

• there is not enough information provided to determine the accuracy

• 8 bit accurate

• = .025

• 8-bits

• 5 codes = 2%

100% = 5 / 2 * 100 = 250 codes/V