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E2E Challengers post your answer to question 5 below in the comments section.
(don't worry your answer won't show until after the contest is over!)
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Absolute Accuracy = (Input Voltage x % of Reading)
Accuracy = .025 ?
But that just doesn't seem right...
Maybe 1 / 20log(2) - (base 10) ?
You are designing a data acquisition system where the tester’s power supply is not accurately calibrated. The specification of the tester indicates it has a rejection ratio of 2%/Volt. Your analysis shows five codes were incorrect. What is the accuracy of your system?
i think something is missing in the question , but it should be (5 codes out of how many sent) give the accuracy then also need to know what voltage the system is running at.
there is not enough information provided to determine the accuracy
8 bit accurate
5 codes = 2%
100% = 5 / 2 * 100 = 250 codes/V
Answer: 4mV (1V / 250)
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