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LMV331 Input Voltage Range (V_CM)

LMV331 Input Voltage Range (V_CM)

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Zachary Glickstein
Posted by Zachary Glickstein
on Apr 17 2012 07:52 AM
Prodigy50 points

I am looking to clarify the meaning of the parameter V_CM, Input Voltage Range, from page 3 on the LMV331 datasheet.  This value is listed as -0.1V to 4.2V given a VCC of 5V, I am trying to verify if this relates to an absolute maximum for the inputs to the part or if it relates to the common mode input.

The input common mode voltage for an op-amp is (V_IN+ + V_IN-)/2, the name of the parameter implies an absolute range, but letters in the symbol, V_CM, implies this parameter relates to Voltage Common Mode. 

With VCC=5V and one input being 4.5V and the other input being 2V will this violate the V_CM parameter for this component?

LMV331
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  • Paul Grohe
    Posted by Paul Grohe
    on Apr 17 2012 10:53 AM
    Verified Answer
    Verified by Zachary Glickstein
    Expert4295 points

    HI Zachary,

    The common mode limit is an absolute for each pin, not the average of the two pins. The formula is correct, but not applicable...

    Comparators can have differential voltages of several volts, so one input does not get a "free-pass" because the other input is at a much lower voltage.

    A VCM limit of 4.2V means do not go above 4.2V....

    So, yes, if one input is at 4.5V, you are violating the VCM specification, regardless of what  is on the other input.

    You will need a R-R input device like the LMC7215 or TLV3401.

    Regards,

    Paul Grohe

    Integrated Signal Chain Applications, SVA

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  • Zachary Glickstein
    Posted by Zachary Glickstein
    on Apr 17 2012 16:51 PM
    Prodigy50 points

    Thanks, this ansewers my question.

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  • Ron Michallick
    Posted by Ron Michallick
    on Apr 18 2012 11:42 AM
    Verified Answer
    Verified by Ron Michallick
    Mastermind30440 points

    Zachary,

    The LMV331 only needs one input to be in the common mode range to have a valid output.
    If both inputs are above the maximum common mode range or either input is below ground then the output is undefined.
    Neither input should exceed VCC.

    Your example voltages will provide a good output.

    Regards,
    Ron

     

    Regards,
    Ronald Michallick
    Linear Applications

    TI assumes no liability for applications assistance or customer product design. Customer is fully responsible for all design decisions and engineering with regard to its products, including decisions relating to application of TI products. By providing technical information, TI does not intend to offer or provide engineering services or advice concerning Customer's design. If Customer desires engineering services, the Customer should rely on its retained employees and consultants and/or procure engineering services from a licensed professional engineer (LPE).

     

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