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VCA824

This question is not answered
Wilson Teo
Posted by Wilson Teo
on Feb 29 2012 09:22 AM
Prodigy190 points

Hi,

Can I know what is the input signal range (voltage level) for the VCA824? I was told that the signal will be clipped if the input signal exceed 60mV (prior to any Gain)

Please advice.

Thanks.

VCA824 VCA824 Input Range
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  • Luke Lapointe
    Posted by Luke Lapointe
    on Feb 29 2012 09:28 AM
    Expert4170 points

    Wilson,

    60mV is most likely fine, but it depends on what your supply voltages are.

    According to page 3 of the VCA824 datasheet, given +/-5V supplies, the most negative input voltage is -2.1V and the most positive is 1.6V. That is the most negative voltage should be 2.9V above the negative rail and the most positive voltage should be 3.4V below the positive rail.

    Regards,
    Luke Lapointe
    High Speed Amplifiers

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  • Wilson Teo
    Posted by Wilson Teo
    on Feb 29 2012 10:44 AM
    Prodigy190 points

    Hi,

    I have my VCA824 on +/-5V supply voltage. But the waveform is clipped when the input source is:

    Waveform type: Sine-wave,10KHz

    Vpp : 60mVpp

    I think I will do a check on my physical hardware again. Thanks.

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  • Luke Lapointe
    Posted by Luke Lapointe
    on Feb 29 2012 18:15 PM
    Expert4170 points

    Wilson,

    I think you are on the right track to check the hardware first. I would also use a multimeter and check the DC voltages as well as the impedance around the board to make sure everything is connected how you expect. Sometimes there is a loose wire or connection that can make the circuit act unexpectedly.

    If everything looks correct and you still see the issue, then you can upload your schematic and we can take a better look.

    Regards,
    Luke Lapointe
    High Speed Amplifiers

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  • Wilson Teo
    Posted by Wilson Teo
    on Mar 21 2012 10:22 AM
    Prodigy190 points

    Hi,

    We had got it figured out after some testing.

    By setting my desired Av = 40V/V, RG=18R and RF=402R. My Vin(Vpp) is limited to around 100mVpp. This is due to the characteristic of the VCA which followed the following equation: Vin(Vpp)=2*RG*IRGMAX

    Right now, I'm preparing to change my RF and RG to get a higher input dynamic range. 

    Can I know if there is any relationship between input frequency with the RF and RG?

    Thanks.

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  • Bart Stiller
    Posted by Bart Stiller
    on Mar 27 2012 17:06 PM
    Intellectual1480 points

    Wilson,

    Your motivation for changing Rf and Rg to "get a higher input dynamic range" is unclear.  With Rg set to 18ohms, as you describe, you have Vin(Vpp) = 2*RG*IRGMAX = 93.6mV.  In a system configured for Avmax = 40, this corresponds to a maximum output voltage of 3.74V, very close to the maximum capability of the device.  If you were to increase the input voltage range, without lowering Avmax, you will begin to clip on the output, similar to Figure 72 of the datasheet.  So any attempt to increase the input dynamic range should be coupled with a decrease in Av, in order to remain within the output voltage limitations of the device.  These and other design considerations are summarized on page 25 of the VCA824 datasheet.

    Regarding Rf and Rg versus frequency, since the output stage of the device is a current feedback amplifier, higher values of Rf result in continually lower bandwidth.  To achieve frequency performance similar to that in the datasheet, it is recommended that Rf not exceed 500ohms.

    Regards,

    Bart Stiller

    High Speed Amplifiers

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  • Wilson Teo
    Posted by Wilson Teo
    on Apr 02 2012 09:28 AM
    Prodigy190 points

    Hi,

    Thanks for your reply. Actually, I do require a large input dynamic range of 0 to 2Vpp.

    The VGA design should ideally be able to amplify the signal when it is small and attenuate the signal when it is large. As the output of the VGA is 'piped' into the ADC, I will need to constantly maintained my output of VGA to be around 1Vpp to make use of the full ADC range.

    However, I realised that the performance of VGA degraded when the input dynamic range is set to 2Vpp.

    Can I know TI recommendation for Rf and Rg value to achieve a 2Vpp? with Av from 0V/V to 20V/V (min)? 

    Or is there any other suitable chipset which you will recommend?

    Thanks.

    P/S: My signal frequency is approx100MHz

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  • Hooman Hashemi
    Posted by Hooman Hashemi
    on Apr 02 2012 12:37 PM
    Expert3910 points

    Hi,

    I've jumped into this rather late. But, here is my 2 cents anyway!

    I'd pick the value of RG to make sure I won't be limited by I_RG with your 2Vpp input. That means RG= 1Vp / 2.6mApp = 385ohm.

    Set RF=500ohm to get the best speed / frequency response. Add another amplification stage to increase the gain to the 20 V/V that you are looking for.

    Hope this helps.

    Thanks,

    Hooman

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  • Wilson Teo
    Posted by Wilson Teo
    on Apr 03 2012 10:19 AM
    Prodigy190 points

    Hi,

    Thanks for your reply. 

    Can I know TI recommendation on RG and RF (based on VCA824) for the following:

    (1) 0V/V to 1V/V

    (2) 0V/V to 20V/V

    If it is possible, can TI  provide the input dynamic voltage range and expected bandwidth for setting (1) and (2)? Also, will like to know if the linearity for setting (1) will still hold?

    Next, do TI or NS has any VGA product which can meeting the following requirement:

    Input Voltage Range : 5mV (small signal) to 2V (large signal)

    Output Voltage Range : 900mV (small signal to amplify as much as possible, large signal to attenuate)

    Dynamic Gain Range : 0V/V to 40V/V (Linearity is the main priority, follow by the maximum gain)

    Signal Frequency : approx. 100MHz

    Control via : Analog voltage (Control algorithm will come from my uController and DAC)

     

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