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DRV8301 kit - OPA365 simulation

DRV8301 kit - OPA365 simulation

This question is answered
indiantuktuk
Posted by indiantuktuk
on May 17 2012 05:02 AM
Expert1485 points
Low-Side Current Sense-BiDirectional_OPA365.TSC

Hi,

I am unable to simulate OPA365 opamp performance.  OPA365 is used in DRV8301 EVM.  Attached the TINA9 file and the DRV schematics (C:\ti\controlSUITE\development_kits\DRV830x-HC-C2-KIT_v103\~DRV830x-HC-EVM-HWdevPkg\DRV830x_RevC_HWDevPKG\Schematic).

Pl help me to simulate the opamp.

thx

Indiantuktuk

OPA365
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  • John Miller - WEBENCH Design Center
    Posted by John Miller - WEBENCH Design Center
    on May 17 2012 09:17 AM
    Expert4735 points

    Thank you for your inquiry.

    The OPA365 is a device that is supported by our Precision Amplifier team.

    Your inquiry is being move to their forum so they can help you with your inquiry.

    They have a great deal of experience using TINA to optimize circuit design and they will be able to help you with any questions you have.

    Thanks & Regards,

    John

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  • John Caldwell
    Posted by John Caldwell
    on May 17 2012 15:22 PM
    Expert6535 points

    To understand what is wrong with this circuit, take a look at voltage source VS4. For simplicy, we will consider the case when there is zero voltage drop across the shunt resistor:

    In this case, the voltage from VS4 is divided by 2 from the resistor divider formed by R1 and R83. Therefore half the value of VS4 appears at the non-inverting input of the OPA365. We know that signals at the non-inverting input of an opamp are amplified by the equation 1 + RF/RG, and with the values shown above, this will give a gain of 11. In your simulation you have VS4 set to 1.65V, so the opamp wants to drive it's output to (1.65 / 2) * 11 = 9.075V. However, the opamp only has a 3.3V power supply and so its output is forced close to this power supply voltage. If you would like 1.65V with 0 current through the shunt than the voltage at the non-inverting input needs to be 1.65V / 11 = .15V and because of the voltage divider VS4 will need to be twice this value: .15V x 2 = .3V. Try setting VS4 to .3V and see if your circuit functions properly.

    Looking at the circuit as a whole, from the goals you wrote in the tina file, you want a 3V span, centered around 1.65 for +/-60A of current in a 2mOhm shunt. This means that you need a gain of 12.5 ((span/2)/(/.12V). The voltage drop across the shunt will see the OPA365 as an inverting amplifier and will be amplified by the equation (-RF / RG), so the ratio of R5 to R4 must be 12.5. The gain applied to the non-inverting pin will be 1 + (R5/R4) and this means the ratio of R1 to R83 must also be 12.5 if you are to use a value of 1.65V for VS4. Standard 1% resistor values with these ratios are shown below, but any resistor values that have the proper ratio will work:

    Performing a DC sweep of VG1 from -.12V to .12V to mimic the shunt voltage gives:

    John Caldwell

    Analog Applications Engineer

    PA Linear Apps

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  • indiantuktuk
    Posted by indiantuktuk
    on May 17 2012 20:14 PM
    Expert1485 points

    Hi John,

    Thanks for the immediate response.  Did you have a look at the schematics of DRV8301 at page 7 (available in controlsuit).  The goals mentioned are derived from the schematics to the best of my understanding (like 1.65V etc) and request you to confirm if its deviating. If I am right the Op amp is also doing summing of voltages from 3 phases.  How to simulate such condition?.

    Currently I would not like to change any resistor values from the schematics / kit.  I was trying to decipher the ADC values from the board like how much current is flowing thru the power board etc.

    Pl suggest.

    Thx

    Indiantuktuk

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  • John Caldwell
    Posted by John Caldwell
    on May 18 2012 15:04 PM
    Verified Answer
    Verified by indiantuktuk
    Expert6535 points

    I previously had not seen the schematic because I do not support the DRV8301 part. Looking at the schematic, yes this is a differential summing amplifier that sums the voltages across the three shunt resistors. You should notice that the value you use for R1 in your TINA schematic does not match the schematic for the EVM, it is 49.9k not 4.99k. This circuit can be simulated in TINA using three current generators each with a specified phase shift (available for sinusoidal waveforms) and doing a transient simulation. 

    John Caldwell

    Analog Applications Engineer

    PA Linear Apps

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  • indiantuktuk
    Posted by indiantuktuk
    on May 19 2012 11:53 AM
    Expert1485 points

    Thanks John for the valuable inputs and for catching the error in my schematics.  I would run the simulation and understand the outputs.  Please suggest any tips to get the sinusoidal wave form simulation with TINA.

    thx

    Indiantuktuk

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  • John Caldwell
    Posted by John Caldwell
    on May 21 2012 15:04 PM
    Expert6535 points

    You may change the input waveform to sinusoidal by double clicking on the current generator to open this dialog:

    The default signal is "unit step", click in this box to highlight unit step, and then click on the "..." button. This brings up the new window:

    Click on the button for a sinusoidal waveform and enter the specifications for your desired waveform.

    John Caldwell

    Analog Applications Engineer

    PA Linear Apps

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