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PCM5100 output filter

PCM5100 output filter

This question is answered
Peter Mix
Posted by Peter Mix
on Dec 31 2011 02:15 AM
Prodigy170 points

In the datasheet for the PCM5100, the recommended output filter is a 470 ohm resistor and a 2.2nF (.0022uF) cap.  This has an approximate -3dB filter point of 153 kHz.  However, the datasheet for the PCM510xEVM-U eval board uses 100 ohms and a 22 nF (.022 uF) cap.  That combo has a -3dB point of about 72 kHz.  Why the discrepancy?

Thanks,

PeterM

PCM5100 output filter i2s
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  • Don Dapkus
    Posted by Don Dapkus
    on Dec 31 2011 17:40 PM
    Guru101715 points

    Hi, Peter,

    Because different people write the d/s versus design the EVM.

    Thanks for pointing that out. We will try to fix them to be consistent.

    -d2

    -----

    Don Dapkus

    Audio Applications Engineering Manager

    Dallas, TX USA

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  • Peter Mix
    Posted by Peter Mix
    on Jan 11 2012 01:54 AM
    Prodigy170 points

    So which is the actual preferred filter?

    Thanks,

    PeterM

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  • Don Dapkus
    Posted by Don Dapkus
    on Jan 25 2012 22:26 PM
    Verified Answer
    Verified by Peter Mix
    Guru101715 points

    Hi, Peter,

    Sorry for the delay. I'd go with what's on the EVM as we have thoroughly tested that combination.

    -d2

    -----

    Don Dapkus

    Audio Applications Engineering Manager

    Dallas, TX USA

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  • B. Bowling
    Posted by B. Bowling
    on Aug 03 2012 06:12 AM
    Prodigy175 points

    I have a follow-on question to this thread - what type of output stage does the PCM5100 have - is it a push-pull, class A, etc? Its not specified in the datasheet anywhere I can find.

    Thanks - Bruce

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  • Akio Ito
    Posted by Akio Ito
    on Aug 05 2012 21:02 PM
    Prodigy10 points

    TI has recommended fc=54kHz as 2nd order LPF in the PCM DAC datasheets.
    Why fc=54kHz? I think as follows.
    The frequency response of N-order Butterworth LPF is;
    1/sqrt((f/fc)^(2*N)+1)
    N=2, 20kHz, fc=54kHz
    -10*log10((20/54)^4+1) =-0.081 dB

    For the response at 20kHz within -0.1dB,
    fc =f/(10^(2*0.1/20)-1)^(2*N))
    =20000/(10^(2*0.1/20)-1)^4)
    =51.195 kHz

    In case of 1st order LPF,
    fc =20000/(10^(2*0.1/20)-1)^2)
    =131.04 kHz

    In case of the value of PCM5100 datasheet,
    N=1, 20kHz, fc=153kHz
    -10*log10((20/153)^2+1) =-0.074 dB

    The value of datasheets may be designed to keep the frequency response within 0.1dB.

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  • B. Bowling
    Posted by B. Bowling
    on Aug 23 2012 15:20 PM
    Prodigy175 points

    I am still looking for an answer to this - what type of electrical output stage does the PCM5100 have?

    Thanks - Bruce

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  • Don Dapkus
    Posted by Don Dapkus
    on Aug 23 2012 21:54 PM
    Guru101715 points

    Hi, Bruce,

    Sorry we missed your post. Let me check tomorrow and get back to you.

    -d2

    -----

    Don Dapkus

    Audio Applications Engineering Manager

    Dallas, TX USA

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  • Don Dapkus
    Posted by Don Dapkus
    on Aug 24 2012 07:38 AM
    Verified Answer
    Verified by Don Dapkus
    Guru101715 points

    Hi, Bruce,

    It's push-pull.

    I'm curious -- why is this information needed? How does it help you in your design or comparison to a competitor's part? I'm kind of new to the codec world; in fact, my boss like to tease me and call me an AmpHead.

    -d2

    -----

    Don Dapkus

    Audio Applications Engineering Manager

    Dallas, TX USA

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  • Ramgopal Divakar
    Posted by Ramgopal Divakar
    on Aug 24 2012 08:34 AM
    Prodigy10 points

    Hi!

    I had asked Bruce to find me the answer. So can I drive it directly to an op amp inverting amplifier adjust gains for increasing or lowering volume? I am not familiar with PWM (class D) circuits and wanted to make sure this isn't that.

    Divakar

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