Hi,First time I'm messing with ADC's.I'm trying to find the usable bits of an ADC using the following article as the reference. http://www.analogzone.com/acqt0515.pdf What i don't understand is that how the author converted the TUE 0.1%FSR to 9.97bits(rms). Also as he mentioned in the conclusion when i use the square root of the sum of the square method for both TUE and ENOB I'm getting different value.
I would appriciate if somebody could elaborate this..Thanks,
Gokul
Hello Gokul,
I used the following equations:
Effective Number of Bits (ENOB) = ln(Full Scale Range/Noise)/ln(2)
ENOB= ln(1/(percent Error))/ln(2)
ENOB=ln(1/(0.1/100))/ln(2) = 9.965 = 9.97bits
TUE = 100 percent * (square root((.003/100)^2+(.1/100)^2+(.003/100)^2))
TUE = 0.1%
Let me know if this helps,
Thank you,
Luis