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DLP7000: Is DLP7000 symmetrical? Let it works on off state, use a 532nm laser illuminate it, and expect that the reflected light is vertical to DLP7000's flat state, is this way right?

Part Number: DLP7000

I want  to use a 532 nm laser light to illuminate the DLP7000, and expect that the reflected light is vertical to  DLP7000's flat state. In this situation, DLP7000 can works in off state or on state. I am wondering if both

stated can be used, and whether they are same or not.  Because when I let it work in off state, a strong diffraction is seen, which is not good for my system.

I will appreciate it very much if anyone can help me.

Thanks in advance.

  • Hello Jingwei,

    Welcome to the DLP section of the TI-E2E community.

    I am a little unclear the orientation of your illumination.  Is your illumination normal to the DMD window (same as vertical to flat state) or is your illumination from the top left corner at 24° from the vertical?  

    Is it possible to make a simple diagram of how you are illuminating the DMD? 

    For clarity we refer to the "on" state when a mirror is tipped 12° toward the upper left corner of the DMD and the "off" state when the a mirror is tipped 12° toward the lower right corner of the DMD.  The "flat" state is when a mirror in nominally parallel to the bottom the package.

    Note that there is a border of mirrors around the active array that are permanently in the "off" state when the DMD is powered.  This is often referred to as the "Pond of Mirrors" or POM. 

    Also the aperture shield on the DMD is not symmetric and is not designed for full array illumination at F3 or smaller from the "off" state side (i.e. the lower right corner).

    If your beam will not extend to the edge of the active array then micromirror operation is symmetric and the aperture is not an issue.

    Fizix

  • Hi Fizix,

    Much glad to see your answer.

    The diagram is as follows. I  want the reflected light is vertical to the flat state. Now I let DPL7000 works on "off" state, as Figure 2 shows. But the diffraction is too high, which is not good to my system.

    The beam I used is larger than the active array. I want to know, in this situation, does DPL7000 must work on “on” state, as Figure 1 shows?  Or, in other words , is the Figure 1 the only right operative state?

    Thank you very much for you reply.

  • Hello again Jingwie,

    I assume you drawing an individual micromiror.  Then in that case I do not understand why there would be a difference other than orientation.  I would expect that there would now be a "strong diffraction" on the "on" side.

    Also, if your beam is bigger than the array if you operate by illuminating from the lower right, then you will have a permanent bright border.

    Is your beam collimated or do you have an NA (i.e. f#)?

    Fizix