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TXS0102 - With higher drive current.

Mani Kumar
Intellectual 320 points
Other Parts Discussed in Thread: TXS0102, PCA9306

Hi,

Selected TXS0102 part, but not able to use in current design because of following:

1. Output drive current is in micro Amps - Required in milliAmps.

2. V IL max is 0.15V - Required minimum 0.2V

Please recommend alternates for bi-directional buffers.

Regards,

Mani

  • 0
    TI__Expert 6430 points

    Hi Mani,

    For TXS01XX serials, they are specific design for open-drain application. Thus, the circuits design is based on transmit gate architecture. When input is low, the transmit gate is on and logic low signal pass the transmit gate. There is a voltage drop between sides of the transmit gate. The value could be 100-200mV. Therefore, output voltage should be equal to input voltage + dropped voltage and output voltage also is reignited as low. In general, 0.4V will be reignited low in 2.3V-5.5V supply on VCCB.

    This is the reason that Vil is 150 mV.

    For output driver current, it will be more than 15mA during transition edge since one-shot circuit will provie more driver current.

    Thanks

    Wei

  • 0 in reply to Wei Lang
    TI__Expert 6430 points

    Hi Mani,

    For alternative part, please refer to PCA9306.

    Thanks

    Wei

  • 0 in reply to Wei Lang
    Intellectual 320 points

    Thanks Wei for the reply,

    For suggested part PCA9306, i could not find out the V IL and drive current parameters in the datasheet.

    Please let me know those parameters.

    Regards,

    Mani

  • 0 in reply to Mani Kumar
    TI__Expert 6430 points

    Hi,

    'Vil' will depend on external resistor since transimit gate will on state when input is low logic.  When input is low logic, the driver will sink current introduced by input side pull-up resistor and output side pull-up resistor. The transmit gate ron also is relative with 'Vil'. Becasue output voltae 'Vol' will be equal to (Vil +Vron). Vol should be low than 0.4-0.7 which depend VCCB voltage. Assuing Vol is 0.4V, then Vil= Vol-Vron. Vron will be equal to Vron*Io.

    Since Vil will depend on these factors, Vil is complicated to give exact range.

    Thanks