It has been mentioned that cc2540 minidk has 256KB Programmable memory and 8 KB RAM ,but my question is "how it is possible to load 324KB of keyfob_demo.hex in to the keyfob ,which has 256 KB of memory ?
That demo application is working fine for me .This question is to understand the memory consumption of cc2540.
Thanks in advance
The file size of the .hex does not reflect the actual size of the image that is written to the CC2540 SoC.
To see the size of the image written to the CC2540, you can use IAR. After you've built your project, have a look in the .map file found in the "Output" folder (Left frame of IAR). At the bottom you'll find the CODE memory, which is what you are looking for.
I think you are looking at the file size on the PC and not the size of the image. The file is not a binary file; the format is intel-hex, and it represents an image of 115 KB.
thanks for your reply !
All content and materials on this site are provided "as is". TI and its respective suppliers and providers of content make no representations about the suitability of these materials for any purpose and disclaim all warranties and conditions with regard to these materials, including but not limited to all implied warranties and conditions of merchantability, fitness for a particular purpose, title and non-infringement of any third party intellectual property right. TI and its respective suppliers and providers of content make no representations about the suitability of these materials for any purpose and disclaim all warranties and conditions with respect to these materials. No license, either express or implied, by estoppel or otherwise, is granted by TI. Use of the information on this site may require a license from a third party, or a license from TI.
TI is a global semiconductor design and manufacturing company. Innovate with 100,000+ analog ICs andembedded processors, along with software, tools and the industry’s largest sales/support staff.