Hello,
Do you know the spec of input bias current of internal op amp.? I can't get the data in datasheet.
Please reply, thank so much!
This thread has been locked.
If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.
As you mention before, could you let me know the around number of input impedance and input bias current?
In my application, the op positive input is from 3V divided voltage with a several mega ohm resistor. The large divided resistor is for power saving, but I have concern about op input driving. Please see attached figure and feedback the answer.
Hi Jay,
The input bias current of the opamp is simulated to be around 100pA so I think the 1M resistor should be fine.
I'm wondering do you need the battery sense voltage for external purposes or could you just use the battery monitor included in the CC2540 ADC? Or is it that this 3V supply you are monitoring is not connected to the CC2540?
Regards,
BK
Hi BK,
Our production feature should have battery monitor. I need divided resistor due to cc2540 operating on 2.1V. For power saving, the divided resistor prefer to much bigger. I can't feed the divided voltage to ADC directly becuase the input bias current of ADC looks more than op amp. So I use unit gain op amp as a buffer, then feed to ADC.
BR
Hi Jay,
That makes sense. Another option which some people use is that when they want to read the voltage they use a GPIO to activate a switch. The switch then allows current to flow through a low resistor divider. In this scenario you won't be burning current all of the time. You can see a schematic illustration in this post, but you have to be careful to select low enough resistors since the ADC impedance is 197k.
http://e2e.ti.com/support/low_power_rf/f/538/p/335327/1170097.aspx#1170097
Regards,
BK