Quetion 1:IN pru074-P62 said:When AMI = 1:....,For HECC mode(ECanaShadow.CANMC.bit.SCB = 1),did the "AMI" refer to LAM[n].LAMI?
For example,There are two notes: note A:Configure eCAN for HECC mode(ECanaShadow.CANMC.bit.SCB = 1).Mailboxes0 as Rx. MSGID and LAM are set as bellow:
//IDE=1."don't care,The bit overwritten by transmitted message;AME=1,acceptance mask is used;AAM=0,"don't care" for receive
//box; ID=0 ECanaMboxes.MBOX0.MSGID.all = 0xC0000000; /*LAMI=1 . 29_bit MASK = 0,0000,0000,0000,1111,1111,1111,1111 */ ECanbLAMRegs.LAM0.all = 0x8000FFFF;
Question 2:IDE=1: although set so,but Because LAM0.LAMI=1,The IDE bit of the receive mailbox is overwritten by the IDE bit of the
transmitted message,Is't so?Ref:spru074-P62.
note B:Configure eCAN for HECC mode(ECanaShadow.CANMC.bit.SCB = 1),Mailboxes0 as Tx.MSGID is set as bellow(transmit_box
needn't LAM)://IDE=1,Identifier extension; AME=0,don't care for transmit mailboxes; AAM=0,Normal transmit mode;29_bit
ID=0,0000,0000,0000,1010,1010,1010,1010 ECanaMboxes.MBOX0.MSGID.all = 0x8000AAAA;
Question 3:When transceive successfully, two side MSGID are the same: ECanaMboxes.MBOX0.MSGID.all = 0x8000AAAA .Is't so?
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