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TMP006 question -- how to handle the view angle issue?

Other Parts Discussed in Thread: TMP006, TMP007

Hello,

It is recommend that the distance (d) between TMP006 and target should be less than half of the radius of target (r).

But in our application, the d is 10mm, and the target is a 14mm*14mm copper. That means d>>r/2.

Is there any solutions to handle this issue? TMP006 sensor will be designed in a plastic housing.

Thanks

Guanmian Xu

  • Hi,

    The TMP006 response is a function of the angle theta, scales as sin^2 (theta). The TMP007 product data sheet, SBOS685, section 7.3.2 shows the definition of theta in terms of the distance, d, and the object radius, D.

    In these terms sin^2 (theta) = (D^2)/(D^2 + d^2). For your values of d=10mm and D=14/2=7mm, this becomes

    sin^2(theta) = 49/(49 + 100) ~ 0.33,

    meaning you will receive about 1/3 the radiation compared to having the detector right next to the copper plates. If you use one of the techniques we talked about previously to increase emissivity to >0.7, then this geometry should work OK.

    Regards,

    Werner