Hi,
I'm currently evaluating EVM for BQ24640
VBAT measured voltage is 0.8423V with open load (no load)
The R14 = 0.8436MΩ(measured by multimeter) & R15 = 100kΩ
If based on formula below, the VBAT should 19.8156V
Formula Vout = 2.1V x [1+R14/R15]
Remark other condition:
a)JP1 = short by jumper BATDRV with BATDRV_IN
b)JP2 = short by jumper ACDRV with ACDRV_IN
c)JP3 = short by jumper VREF with VPULLUP
d)JP4 = short by jumper VPULLUP with CHGEN
e)JP5 = short by jumper VPULLUP with LEDPWR
Kindly advise.
