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What requirement must BQ24192 meet in order to reach max charge current 4,5A?

Phuoc_Do79
Prodigy 20 points
Other Parts Discussed in Thread: BQ24192

Hi!

After read datasheet of BQ24192, I know it's a such great IC charger with charge current up to 4,5A. I only want to charge battery, so What requirement must BQ24192 meet in order to reach max charge current 4,5A (or as high as possible)? And what elements must I attend to when I design and make board? I use SMD.

Thanks and Regards,

Phuoc Do!

  • 0
    TI__Expert 4285 points

    Hi Phuoc,

    Glad to hear you liked BQ24192's feature!

    BQ24192 will reach its highest charge current when it is in fast charge mode(please refert to Fig 14, in Page 19 in Datasheet). Other than that, there is not much "special" requirement needed. Maybe you can elaborate what you are really looking for here.

    If you want to design a board, I recommend use BQ24192 EVM as a starting point. We also have some layout guidelines at the end of datasheet.

    Best Regards,

    Linhong

  • 0 in reply to Linhong Qin
    Prodigy 20 points
    Hi Linhong Qin !
    Thanks for your answer!
    Finally, I have made a charger board, I use MCU to control BQ24192. It is so great!
    Unfortunately, when I test, it can only charge at 1700mA, when i set higher, it drop down 600mA. It makes me disappointed very much. I do not know what is wrong!
    Something about my board:
    - Apdater: 12V/2A
    - Vbus= +12V
    - Sys1 connect to Sys2 and supply for PG Led and STAT Led.
    - PSEL connect to GND.
    - OTG pull +5V via R 10K.
    - R at ILIM pin = 110 Ohm --> input current limit > 3A
    - TS1 connect to TS2, R1=10K and R2=10K.
    - PGND1 connect to PGND2 and PAD.
    About my program:
    - UART: communicate with PC.
    - I2C: communicate with BQ24192.
    - In main program, after initialization, it do nothing and wait for UART interrupt.
    About result of my test:
    - Battery: Ipad mini (Li-Po: 3.72V 4440mAh)
    - Voltage: 3675mV
    - So good at: 1600mA, 1700mA.
    REG00= 37 REG01= 1B REG02= 48 REG03= 20 REG04= B2
    REG05= 88 REG06= 1F REG07= 8 REG08= A4 REG09= 0
    - But when i set 1800mA , immediately, it drop down 600mA.
    REG00= 37 REG01= 1B REG02= 50 REG03= 20 REG04= B2
    REG05= 88 REG06= 1F REG07= 8 REG08= A4 REG09= 0
    - In 1800mA, I read REG08, sometimes it charge (REG08= A4 ), sometimes stop charge(REG08= 84 ).
    Can you tell me why it drop down 600mA, Linhong Qin? I really love BQ24192 and want to increase charge current ( at least 3A).

    Thanks and Regards,

    Phuoc Do!
  • 0 in reply to Phuoc_Do79
    TI__Expert 4285 points

    Hi Phuoc,

    I don't see obvious problem from your data. But I couldn't reproduce your problem on EVM either. Could you please double check the register settings when you have problem(eg. force a read to ensure data is updated)

    One thing I can think of is thermal regulation. In this case, we should see fault.

    Regards,

    Linhong

  • 0 in reply to Linhong Qin
    TI__Expert 4285 points

    Hi Phuoc,

    The other possibility is that we might have hit OCP limit. Our lower limit of this spec is 5.3A.  It is possible when higher current charging is enabled, charging current plus inductor ripple have exceeded that limit momentarily. IC was triggered to enter a protection mode.

    To verify that, ideally we need to see the waveform of inductor current, with and without the problem. Are you able to get that?

    To indirectly prove it, you can lower the input voltage or increase inductance. This should reduce inductor ripple current and help push the "current fall-off" point higher.

    Best Regards,

    Linhong