• Join
  • Sign In with my.TI Login
Texas Instruments
  • Products
  • Applications
  • Tools & Software
  • Support & Community
  • Sample & Buy
  • About TI
Sample & Purchase Cart Sample & Purchase Cart
  • Search
  • Advanced
TI E2E™ Community
  • Support Forums
  • Blogs
  • Groups
  • Videos
  • 简体中文
  • More ...
TI Home » TI E2E Community » Support Forums » Power Management » Non-Isolated DC/DC » Non-Isolated DC/DC Forum » TL2575 Heat Problems
Share
Non-Isolated DC/DC
  • Forum
  • Announcements
  • E2E Wiki
Options
  • Subscribe via RSS

Forums

TL2575 Heat Problems

This question is not answered
John Crawford
Posted by John Crawford
on Jul 26 2012 10:47 AM
Prodigy60 points

Hi,

I'm working on a project where we have a 24VDC input and I'm using the TL2575-33 switching regulator to get that down to 3.3VDC. This is the power supply for a relatively small and simple PCB with two other TI RF chips (CC2530 w/ CC2591 amplifier) and a power metering chip. The problem we're having is that when we test the TL2575 through-hole package in the lab on a perf board, the heat the TL2575 puts off is enough to burn your finger. I'm using all the suggested parts as given in the datasheet with the components as close to the TL2575 as they can be.

Based on our calculations for current, we are going to need around 100 mA normally with a peak consumption around 200-230mA when at full RF power. I have a schottky diode rated at 1A and 40V, the caps are at the recommended values and are rated for 50V and the inductor is 680uH. I also tried a 1000uH inductor but still had the same heat problems. To test I hook up a load resistor that simulates 200mA of current.

On the test bench when running at a lower input voltage the heat is not bad but when i get up to around 18-24VDC it starts getting really hot, which i expect. But what I'm wondering is, when I use the DDPACK-5 package and put it on my board, will it be scorching hot still and is this acceptable? Should I have a ground plane around it to help dissipate the heat? I'm assuming I should get a heat sink as well but will this solve my heat problems to a reasonable point?

Thanks in advance for the help,

-John

TL2575
Report Abuse
  • Reply
You have posted to a forum that requires a moderator to approve posts before they are publicly available.
All Replies
  • Avi Chami1
    Posted by Avi Chami1
    on Jul 26 2012 12:21 PM
    Mastermind7405 points

    Some things sound strange, others are not clear. When you say the thru-hole package, is that the PDIP one?

    Your output power is 3.3V x 200mA , approx. 0.65W. With an efficiency of between 70 to 80%, the heat disipated by the device should be of no more than 0.2W. Even with the very bad thermal resistance of the PDIP package, that would ammount to a temp. increase of no more than 20°C.

    It is also not so good that the temperature raises so much for high Vin. The efficiency of the device doesn't change so much... and I have the impression that it gets BETTER as Vin increases.

    You should check all your design carefully. Measure output voltage and output current for several input voltages. Something fishy is going there, according to what you told.

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • John Crawford
    Posted by John Crawford
    on Jul 27 2012 07:29 AM
    Prodigy60 points

    Yes, we are using the PDIP package for testing and we're going to use the TO-263 package when we make our PCB. According to what you said, we're going to have to revisit our circuit again to double check everything it sounds like. Thank you for the advice so far and i'll post more questions if I have them. We basically wanted some verification that this shouldn't be happening...

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • Ron Michallick
    Posted by Ron Michallick
    on Jul 27 2012 10:30 AM
    Mastermind30930 points

    Hello John,

    Be sure to connect all three grounds together on the PDIP package. It is important to do so.

    Measure the input and outputs voltages and current to calculate efficiency and power loss.
    Look at pin 3 (output)  with an oscilloscope, this node is very informative.
    ~ -1V is inductor discharging through diode (switch off)
    ~+VCC is internal switch charging inductor.
    ~+3.3V is inductor current zero (switch off)

    Regards,
    Ron Michallick

     

    Regards,
    Ronald Michallick
    Linear Applications

    TI assumes no liability for applications assistance or customer product design. Customer is fully responsible for all design decisions and engineering with regard to its products, including decisions relating to application of TI products. By providing technical information, TI does not intend to offer or provide engineering services or advice concerning Customer's design. If Customer desires engineering services, the Customer should rely on its retained employees and consultants and/or procure engineering services from a licensed professional engineer (LPE).

     

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
TI E2E™ Community
  • Support Forums
  • Blogs
  • Videos
  • Groups
  • Site Support & Feedback
  • Settings
TI E2E™ Community Groups
  • TI University Program
  • Make the Switch
  • Microcontroller Projects
  • Motor Drive & Control
Other Communities
  • Deyisupport
  • Designsomething.org
  • beagleboard.org
  • TI on Element 14
  • TI on TechXchangeSM
Other Technical & Support Resources
  • WEBENCH® Design Center
  • Product Information Centers
  • Technical Documents
  • TI Design Network
  • TI Technical Articles
  • TI Training

All content and materials on this site are provided "as is". TI and its respective suppliers and providers of content make no representations about the suitability of these materials for any purpose and disclaim all warranties and conditions with regard to these materials, including but not limited to all implied warranties and conditions of merchantability, fitness for a particular purpose, title and non-infringement of any third party intellectual property right. TI and its respective suppliers and providers of content make no representations about the suitability of these materials for any purpose and disclaim all warranties and conditions with respect to these materials. No license, either express or implied, by estoppel or otherwise, is granted by TI. Use of the information on this site may require a license from a third party, or a license from TI.

Content on this site may contain or be subject to specific guidelines or limitations on use. All postings and use of the content on this site are subject to the Terms of Use of the site; third parties using this content agree to abide by any limitations or guidelines and to comply with the Terms of Use of this site. TI, its suppliers and providers of content reserve the right to make corrections, deletions, modifications, enhancements, improvements and other changes to the content and materials, its products, programs and services at any time or to move or discontinue any content, products, programs, or services without notice.

Follow Us Texas Instruments on Facebook Texas Instruments on Twitter Texas Instruments on LinkedIn Texas Instruments on Google+
TI Worldwide | Contact Us | my.TI Login | Site Map | Corporate Citizenship | mobile m.ti.com (Mobile Version)

TI is a global semiconductor design and manufacturing company. Innovate with 100,000+ analog ICs and
embedded processors, along with software, tools and the industry’s largest sales/support staff.

© Copyright 1995-2013 Texas Instruments Incorporated. All rights reserved.
Trademarks | Privacy Policy | Terms of Use