• Join
  • Sign In with my.TI Login
Texas Instruments
  • Products
  • Applications
  • Tools & Software
  • Support & Community
  • Sample & Buy
  • About TI
Sample & Purchase Cart Sample & Purchase Cart
  • Search
  • Advanced
TI E2E™ Community
  • Support Forums
  • Blogs
  • Groups
  • Videos
  • 简体中文
  • More ...
TI Home » TI E2E Community » Support Forums » Power Management » Power Interface » Power Interface Forum » LM5050-1
Share
Power Interface
  • Forum
  • E2E Wiki
Options
  • Subscribe via RSS

LM5050-1

LM5050-1

This question is not answered
1886332
Posted by 1886332
on Apr 02 2012 03:15 AM
Intellectual685 points

Hi,

the schematic of input section can be seen below.

the Output section is disconnected, it means that VBAT don't have any load.

the input voltage is 28V, it means that VBAT1_IN=28V.

the current we measured for this section is 3mA when input voltage is 28V.

according to specification the current should be around 0.6mA for 28V.

please advise how we can reduce the current consumption of LM5050-1?

the FET we are using is PSMN2R6-40YS.

 

 

Thanks,

 

Report Abuse
  • Reply
You have posted to a forum that requires a moderator to approve posts before they are publicly available.
All Replies
  • Donald Jones
    Posted by Donald Jones
    on Apr 02 2012 14:52 PM
    Expert6785 points

    As described here you would be correct to expect 600uA of current.

    I have no idea why you would measure so much current (i.e.3 mA). 

    With 28.0V at Vin, 0V at Off, and Vout open, I have measured 449 uA of input current on the LM5050-1 eval board in the lab.

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • 1886332
    Posted by 1886332
    on Apr 02 2012 15:06 PM
    Intellectual685 points

    Hi Donald,

    Thanks for your reply.

    Can you please measure the currnet in GND(pin 2) as I dont have the EVM here.

    thanks,

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • Donald Jones
    Posted by Donald Jones
    on Apr 02 2012 15:28 PM
    Expert6785 points

    Yes, but it will take awhile as I need to dismount the LM5050-1 from the circuit board. Attempting to simply de-solder and lift the pin from the PCB will typically break the pin off.

    I would expect the pin 2 (Gnd) current to be the same as what I have already measured (i.e the sum of Iin, Iout and Ivs).

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • 1886332
    Posted by 1886332
    on Apr 02 2012 15:59 PM
    Intellectual685 points

    Can you please dismount R1 and replace it with R2, supply voltage to J1 and than to measure the current(Ivs and Iin)?

     

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • Donald Jones
    Posted by Donald Jones
    on Apr 02 2012 16:21 PM
    Expert6785 points

    Is this in addition to, or instead of, your earlier request for ground pin current?

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • Donald Jones
    Posted by Donald Jones
    on Apr 02 2012 17:16 PM
    Expert6785 points

    Confirmed that the LM5050-1 pin 2 (Gnd) current is the sum of Iin, Iout and Ivs.

     

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • Donald Jones
    Posted by Donald Jones
    on Apr 02 2012 17:21 PM
    Expert6785 points

    " ... to measure the current (Ivs and Iin)? ... "

    But do NOT include Iout which is biased though the MOSFET body diode?

    OK, can do.

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • Donald Jones
    Posted by Donald Jones
    on Apr 02 2012 18:42 PM
    Expert6785 points

    I measure Iin+Ivs at 459uA.

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • 1886332
    Posted by 1886332
    on Apr 03 2012 00:55 AM
    Intellectual685 points

    Dear Donald Jones,

    Thank you very much for the support, it was very helpful.

    If there will ne more issues I will contact you.

    thanks,

    BR,

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • Donald Jones
    Posted by Donald Jones
    on Apr 03 2012 11:32 AM
    Expert6785 points

    Did you find the cause of the additional ~2.5mA of current drain?

     

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • 1886332
    Posted by 1886332
    on Apr 04 2012 02:17 AM
    Intellectual685 points

    Hi Donald,

    Not yet. We will wait for the EVM and compare it to our PCB.

    Your test helped us a lot and proved that the IC can fit our requirments.

    Thanks again

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • 1886332
    Posted by 1886332
    on Apr 24 2012 04:55 AM
    Intellectual685 points

    Hi Donald,

     

    The costumer got the EVM and now the problem is more clear:

     

    He measured the current and saw the same problem.

    I will explain the problem:

    when using the EVB as is, there isn't any problem because it's only one device.

    the pins : Vin, Vout and Vs consume the power as in specification.

    BUT when using two devices. the problem appear.

    When there isn't power on pin Vin and there is power in pins Vout, Vs. then the power consumption of Vout,Vs is 3.3mA.

    you can verify the problem by applying power to R1 while there isn't power in Vin on the EVB

     

     

    Please advise how can I reduce the current on Vout, Vs where there isn't power on Vin.

    Thanks,

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • Eugen Lorenz
    Posted by Eugen Lorenz
    on Sep 05 2012 07:23 AM
    Prodigy10 points

    I would recommend to change the connection of VS pins from Vout to Vin. If you read the datasheet on page 2 in Pin Descriptions, TI recommends to connect VS either Vout or Vin. In this case the turn off of the Vin1 will cause the turn off the whole chip and I think it will not more consume the power. If you compare the circuit by customer with one by Donald you see that Donald has connected VS to Vin and measured small current, but customer has connected VS to Vout and measured bgger current.

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
TI E2E™ Community
  • Support Forums
  • Blogs
  • Videos
  • Groups
  • Site Support & Feedback
  • Settings
TI E2E™ Community Groups
  • TI University Program
  • Make the Switch
  • Microcontroller Projects
  • Motor Drive & Control
Other Communities
  • Deyisupport
  • Designsomething.org
  • beagleboard.org
  • TI on Element 14
  • TI on TechXchangeSM
Other Technical & Support Resources
  • WEBENCH® Design Center
  • Product Information Centers
  • Technical Documents
  • TI Design Network
  • TI Technical Articles
  • TI Training

All content and materials on this site are provided "as is". TI and its respective suppliers and providers of content make no representations about the suitability of these materials for any purpose and disclaim all warranties and conditions with regard to these materials, including but not limited to all implied warranties and conditions of merchantability, fitness for a particular purpose, title and non-infringement of any third party intellectual property right. TI and its respective suppliers and providers of content make no representations about the suitability of these materials for any purpose and disclaim all warranties and conditions with respect to these materials. No license, either express or implied, by estoppel or otherwise, is granted by TI. Use of the information on this site may require a license from a third party, or a license from TI.

Content on this site may contain or be subject to specific guidelines or limitations on use. All postings and use of the content on this site are subject to the Terms of Use of the site; third parties using this content agree to abide by any limitations or guidelines and to comply with the Terms of Use of this site. TI, its suppliers and providers of content reserve the right to make corrections, deletions, modifications, enhancements, improvements and other changes to the content and materials, its products, programs and services at any time or to move or discontinue any content, products, programs, or services without notice.

Follow Us Texas Instruments on Facebook Texas Instruments on Twitter Texas Instruments on LinkedIn Texas Instruments on Google+
TI Worldwide | Contact Us | my.TI Login | Site Map | Corporate Citizenship | mobile m.ti.com (Mobile Version)

TI is a global semiconductor design and manufacturing company. Innovate with 100,000+ analog ICs and
embedded processors, along with software, tools and the industry’s largest sales/support staff.

© Copyright 1995-2013 Texas Instruments Incorporated. All rights reserved.
Trademarks | Privacy Policy | Terms of Use