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PTH04T241W turbo trans

Hello

I am using PTH04T241WAD for powering the FPGA.
10 capacitors are connected to its output.
Each capacitor is 100uF, ESR=2mOhm (GRM32ER60J107M MURATA).
How should I correctly define the capacitor's type (Type A or Type B or Type C) for operating in the TurboTrans mode?

What is "C" in the (C х ESR) formula? Is it the total output capacitance or the capacitance of the individual capacitor?

So, what of the following is correct?

10 х 100uF х 2mOhm = 2000 - Type B
or
100uF х 2mOhm = 200 - Type A ?

Best Regards
Alex

  • Alex:

    PT08T241W all ceramic capacitors has  turbo trans table ( page19) specification   Type A-ceramic capacitor .Page 19 . attached

    1. The   individual ceramic capacitor Type "A"   "C" and " ESR"   in figure 10 note  is as you stated. calculation 100uF х 2mOhm = 200# - Type A.table .

    2. The alternate type A  calculation ( 100≤C(µF) x ESR(mΩ) ≤1000 for: 10 quantity x100µF with ESR each 2mΩ

    2a. Absolute # C= 10(quantity) x100(µF) =1000 : ESR=2/10=0.2 (mΩ)  ::total # for type A at 1000(C) x0.2(mΩ) = 200  tape A ceramic capacitors. The type A calculation  limit is 1000 absolute #

    Type A data with  10 x100µF ceramic capacitors , RTT turbo trans resistor ≤5.7kΩ

    Tom

    My direct e-mail  is tguerin@ti.com if you have any additional questions.

    Pages from PTH04T241s Type A capacitors ceramic specification c pth04t241w[1].pdf