• Join
  • Sign In with my.TI Login
Texas Instruments
  • Products
  • Applications
  • Tools & Software
  • Support & Community
  • Sample & Buy
  • About TI
Sample & Purchase Cart Sample & Purchase Cart
  • Search
  • Advanced
TI E2E™ Community
  • Support Forums
  • Blogs
  • Groups
  • Videos
  • 简体中文
  • More ...
TI Home » TI E2E Community » Support Forums » Power Management » SIMPLE SWITCHER® » SIMPLE SWITCHER® - Forum » LM2587 typical boost regulator application
Share
SIMPLE SWITCHER®
  • Forum
  • Announcements
  • Files
  • E2E Wiki
Options
  • Subscribe via RSS

LM2587 typical boost regulator application

LM2587 typical boost regulator application

This question is not answered
Yusong Di
Posted by Yusong Di
on May 11 2012 12:46 PM
Prodigy30 points

Hi, 

Recently I bought several LM2587-ADJ/NOPB, and now I meet some problems with application provided by datasheet.

Input 6V, 1A, DC source. The output side we connect 100ohms power resistor.

Actually, the circuit behaves well with no load, the output voltage is exactly like what we set 12V. However, as 100ohms resistor connect to the output side, the output voltage drop significantly, like 6-8V, and sometimes the chip gets hot and burns out.

Ask for help! How to set the output voltage when we get a load.

LM2587 set output voltage
Report Abuse
  • Reply
You have posted to a forum that requires a moderator to approve posts before they are publicly available.
All Replies
  • Ismail Jorio
    Posted by Ismail Jorio
    on May 11 2012 14:47 PM
    Prodigy675 points

    Hi Yusong,

    When you configure LM2587-ADJ in a boost topology, you have a traight path from input to output. So, when  load the output with 100Ohm, basically you are shorting your supply and bypassing the switch.

    In order to run this application you have to startup with a supply higher than 1A because this can easily reach 1A starting with load deoending on the inductor you are using. Or you slowly increase your load to 100Ohm. (0.12A). An external current limit circuit lower than 5A (current limit of the part) will be a protection not to burn your IC.

    This part is mean for higher output current, you can use lower current parts on the same family or you enter your specs on our Webench tools to suggest optimized solutions for your application.

     

    Regards,

    Ismail Jorio 

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • Yusong Di
    Posted by Yusong Di
    on May 24 2012 14:47 PM
    Prodigy30 points

    You mean the inductor and the load we used is to small? And the load is short the chip.  However, our input is DC regulator which voltage is 6V and current is 1A, that means if the load short the circuit, our output should achieve the outpout voltage we want at startup moment. According to 5 times experiment, our output voltage never exceeded 7V. And that brings that if the load short the circuit, our diode has maximum reverse voltage which is 40V, and it could be impaired. However, what we burned is just IC.

    And with the input current requirement you mentioned, our DC-DC converter burned out with input current exceeding 1.5A. So, I guess that it is the duty cycle problem or the DC-DC internal structure problem?

    LM2587 Burn out not proper
    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
  • Marc Davis-Marsh
    Posted by Marc Davis-Marsh
    on May 24 2012 20:41 PM
    Expert3290 points

    Hi,

    Can you post some more details. If possible it would help if I could see a waveform showing

    Channel 1: Vin.

    Channel 2: Vout

    Channel 3: PIn four ot the 2857, the Switch node.

    The time scale should be such that you can see several pulses on the switch node. One scope shot for no load, and one with the 100ohm load.

    Can you give me a bill of materials for the design you are testing?

    That should help me to diagnose the problem.

     

    I also have a few questions for clarification.

    1) I understood that with the 100ohm resistor tied to the output, the output voltage was 7V.  Is this correct?

     

    Regards,

    Marc

     

     

     

    Report Abuse
    • Reply
    You have posted to a forum that requires a moderator to approve posts before they are publicly available.
TI E2E™ Community
  • Support Forums
  • Blogs
  • Videos
  • Groups
  • Site Support & Feedback
  • Settings
TI E2E™ Community Groups
  • TI University Program
  • Make the Switch
  • Microcontroller Projects
  • Motor Drive & Control
Other Communities
  • Deyisupport
  • Designsomething.org
  • beagleboard.org
  • TI on Element 14
  • TI on TechXchangeSM
Other Technical & Support Resources
  • WEBENCH® Design Center
  • Product Information Centers
  • Technical Documents
  • TI Design Network
  • TI Technical Articles
  • TI Training

All content and materials on this site are provided "as is". TI and its respective suppliers and providers of content make no representations about the suitability of these materials for any purpose and disclaim all warranties and conditions with regard to these materials, including but not limited to all implied warranties and conditions of merchantability, fitness for a particular purpose, title and non-infringement of any third party intellectual property right. TI and its respective suppliers and providers of content make no representations about the suitability of these materials for any purpose and disclaim all warranties and conditions with respect to these materials. No license, either express or implied, by estoppel or otherwise, is granted by TI. Use of the information on this site may require a license from a third party, or a license from TI.

Content on this site may contain or be subject to specific guidelines or limitations on use. All postings and use of the content on this site are subject to the Terms of Use of the site; third parties using this content agree to abide by any limitations or guidelines and to comply with the Terms of Use of this site. TI, its suppliers and providers of content reserve the right to make corrections, deletions, modifications, enhancements, improvements and other changes to the content and materials, its products, programs and services at any time or to move or discontinue any content, products, programs, or services without notice.

Follow Us Texas Instruments on Facebook Texas Instruments on Twitter Texas Instruments on LinkedIn Texas Instruments on Google+
TI Worldwide | Contact Us | my.TI Login | Site Map | Corporate Citizenship | mobile m.ti.com (Mobile Version)

TI is a global semiconductor design and manufacturing company. Innovate with 100,000+ analog ICs and
embedded processors, along with software, tools and the industry’s largest sales/support staff.

© Copyright 1995-2013 Texas Instruments Incorporated. All rights reserved.
Trademarks | Privacy Policy | Terms of Use