02 01 04 03 06 05 08 07 02 00 01 01 60 01 00 00 42 16 0A 00 01 00 00 00 09 CC B4 F0 18 00 00 00 01 00 00 00 00 00 00 00 
 
01 00 00 00 24 01 00 00 18 00 09 00 

2C 00 00 00 F1 10 A7 00 1F 04 00 00 2D 00 00 00 9E 1B AB 00 37 04 00 00 2E 00 00 00 D8 15 8C 00 54 04 00 00 2F 00 00 00 0B 0A 6B 00 70 04 00 00 2C 00 01 00 E3 08 A7 00 1F 04 00 00 2D 00 01 00 7B 0E AB 00 37 04 00 00 2E 00 01 00 75 0B 8C 00 54 04 00 00 2F 00 01 00 45 05 6B 00 70 04 00 00 2C 00 FF FF DA 08 A7 00 1F 04 00 00 2D 00 FF FF 6D 0E AB 00 37 04 00 00 2E 00 FF FF 69 0B 8C 00 54 04 00 00 2F 00 FF FF 3F 05 6B 00 70 04 00 00 2C 00 00 00 4C 0D EA FD 9D 03 00 00 2D 00 00 00 74 14 DE FD B2 03 00 00 2E 00 00 00 6D 11 D2 FD C7 03 00 00 2F 00 00 00 DC 07 A2 FD C7 03 00 00 2C 00 01 00 FA 06 EA FD 9D 03 00 00 2D 00 01 00 BA 0A DE FD B2 03 00 00 2E 00 01 00 22 09 D2 FD C7 03 00 00 2F 00 01 00 20 04 7B 03 C8 02 00 00 2C 00 FF FF F2 06 EA FD 9D 03 00 00 2D 00 FF FF B0 0A DE FD B2 03 00 00 2E 00 FF FF 1C 09 D2 FD C7 03 00 00 2F 00 FF FF 1C 04 A2 FD C7 03 00 00 

0F 0F 0F 0F 0F 0F 0F 0F 0F 0F 0F 0F       


the total bytes is 352. the number of objects is 18. according to my understabding, (352-40-12-12)/16 = 18. It seems my understanding is right in this text.