Other Parts Discussed in Thread: CD74HCT4067-Q1 Hi All,
Since CD74HCT4067-Q1 is bidirectional, can it accept negative input voltages also? If not, is there any analog mux that accepts negative input voltages?
Thanks
Hello Jeff,
See old datasheet (Revision C) below. schs209c.pdf
I have compared the capacitance between them and it seems it is similar in both datasheets.
Unforutnatly, we don't have information on charge injection for either part.
Do they have…
HI. Kameron.
I would consider using the CD74HCT4067-Q1, are there currently any other models with similar performance and more channels to the CD74HCT4067-Q1?
Part Number: CD74HC4067 Other Parts Discussed in Thread: CD74HCT4067 Hi there,
I am using Part No. " CD74HC4067M96" in my circuit as per the suggested circuit dig.
where,
Pin 24 Is VCC_5V
Pin 1 Is MUX out
Pin 12 and Pin 15 Is Ground
MUX…
Hi Clemens
Thanks for the reply but I have some more doubts regarding this
The specified Switch "OFF" Signal Feedthrough for CD74HC4067 at Vcc of 4.5V is -75 dB. So what I am guessing about this parameter value is that if the noise level is higher…
Hi Daniel,
The best option we have for an 8:1 device for this situation is the TMUX1308, its a good general purpose 8:1 mux that can be used for digital or analog signals.
For a 16:1 switch we have two possible options that may fit your needs the…
Since customer’s requirement is +/-5V analog input, which implies recommended VCC to GND/VEE should be close to or higher than 10V without the help of internal charge pump. CD74HC4067’s max supply range is 6V, while CD74HCT4067’s is 5.5V. Neither would…
Hi Kurumi,
I have some concerns with this application - please see below for the concerns as well as a potential work around.
1. you don't need a 12 channel mux - you need a 2 channel 12:1 multiplexer (12 inputs to 1 output and vice versa). We don…
Almerindo,
Unfortunately I know very little about the part except for what is in the datasheet. You might try posting your question in the Logic forum. I would assume that the ESD protection would conduct current and could potentially damage the device…
