Part Number: LP8868U-Q1 Hello TI Support Team,
I am using the LP8868U-Q1 to drive the backlight of an ultrawide display. The converter output is 26 V at approximately 0.34 A, powered from a 5 V input rail.
The circuit is functioning correctly, and…
Part Number: LP8868U-Q1 Tool/software: Hello,
I have installed, LP8868 model in Simetrix but simulation is showing error.
(Input file C:\Users\akanksha.upadhyay\Documents\Elements\design.deck, line 15:
X$U1 L1_N V1_P R3_N C1_P R3_P C1_N R3_N U1_OVP…
Part Number: LP8868U-Q1 Tool/software: Hello,
Thank you for the reply as per your guidance i have installed SIMPLIS but can you kindly tell me where to find LP8868 ic . I searched in LED Driver section but did not did not find it.
In Simplis i went…
Part Number: LP8868U-Q1 Tool/software: Dear Sir,
I have read the data sheet of LP8868, kindly provide me clarification regarding the fact that Vcc which is the output pin of the IC is connected to the fault pin through a resistor ....So if the fault…
Part Number: LP8868U-Q1 Other Parts Discussed in Thread: LP8865Z-Q1 , LP8865C-Q1 Hi there
We are using 4 LEDs in series. Specs below,
VF: 1.6V
IF 700mA
We would like to use analog led driver with dimming option.
Thanks.
Part Number: LP8868U-Q1 Tool/software: Dear Sir,
I am using LP8868-Q1 IC as LED Driver, and is working on its compensation circuit. I have set led current as 820mA and have used 33uH inductor .
But while giving pwm at pwm pin of IC with its frequency…
Part Number: LP8868U-Q1 Tool/software: Hello experts,
Can we use LP8868U for a floating Buck boost topology? Should we use LP8868V? What is the difference between them?
As our customer is pleased if LP8868U can be used for both boat and floating Buck…
Part Number: LP8865C-Q1 Other Parts Discussed in Thread: LP8868X-Q1 , LP8868U-Q1 , TPS922051 , TPS92541-Q1 Tool/software: Dear team,
Q1: Would I know ILIM value for LP8865C-Q1? Datasheet only shows TPS925501 value...
Q2: I consider 5Vin, 24Vout, 0…
Part Number: LP8868Z-Q1 Tool/software: At the bottom of section 8.2.3.2.1 last paragraph it states "ILED = 2A, consider the efficiency as 0.9" and lists the Inductor Current Max of 0.741A
Where and how did we come up with this value of 0.741Amps for…
