TI E2E support forums
TI E2E support forums
  • User
  • Site
  • Search
  • User
  • E2E™ design support >
  • Forums
    • Amplifiers
    • API solutions
    • Audio
    • Clock & timing
    • Data converters
    • DLP® products
    • Interface
    • Isolation
    • Logic
    • Microcontrollers
    • Motor drivers
    • Power management
    • Processors
    • RF & microwave
    • Sensors
    • Site support
    • Switches & multiplexers
    • Tools
    • Wireless connectivity
    • Archived forums
    • Archived groups
  • Technical articles
  • TI training
    • Tech days
    • Online training
    • Live events
    • Power Supply Design Seminar
  • Getting started
  • 简体中文
  • More
  • Cancel


Search tips
Showing 3 results View by: Thread Post Sort by
  • RE: UCC25800-Q1: IC not operating as an LLC

    Hong Huang
    Hong Huang
    Hi, PMP40980 is on secondary side resonance. Yours is on primary side. Since you parallel four transformers, it requires to use the secondary side resonance since there is no clear single resonance can be defined on the primary side with 4 transformer…
    • 8 months ago
    • Power management
    • Power management forum
  • Answered
  • RE: UCC25800-Q1: Multiple isolated secondary windings transformer - Low Power/High voltage

    Eric Reicher
    Eric Reicher
    Resolved
    Hi again Thiago, This configuration is OK for the UCC25800. Please have a look at the following Reference Design: PMP40980 Multiple-output isolated SiC driver bias-supply reference design for onboard charger applications
    • over 2 years ago
    • Power management
    • Power management forum
  • RE: Power isolation solution

    Jonathan Wong
    Jonathan Wong
    Hello Hailey, Thank you for reaching out. Since each output is 1A, is the total power of the system 15.2W? If so, I would recommend the UCC28C59 in a flyback with multiple outputs. This product also has many variations (such as an automotive equivalent…
    • over 2 years ago
    • Isolation
    • Isolation forum

Didn't find what you are looking for? Post a new question.

  • Ask a new question