For this application, I would suggest the REF102. If you want to explore other options, our precision voltage reference portfolio can be found here:
https://www.ti.com/power-management/voltage-reference/series-voltage-reference/overview.html
How you approach…
Part Number: REF102
Dear Tech Support Team,
The customer received part#REF102BU and informed that the top marking is not matched with the datasheet.
The datasheet states the device marking should be "REF 102U B" but the received part showed "REF 102U…
Part Number: REF102 As a one of our project Implementation, we planned to use ref102
So, could you please suggest the reference circuit with component details including Isolation transformer feedback resistor configuration if any
Part Number: REF102 Other Parts Discussed in Thread: REF70 , Hello TI Team, We are trying to use Voltage REF IC for our application with requirement of noise <4uVpp, temperature coefficient 5pp/deg C. let us know if we can use REF102BU. Please clarify the…
Part Number: REF102 Hello, I would like you to confirm whether you have thermal information for each package of REF102. If you have, could you please share it to me ? BR,
Part Number: REF102 Hi Experts ,
Good Day ,
Can you please check and confirm below DIE Markings are consistent with the MPN : REF102CU/2K5 ?
Looking forward for your valuable support to accept the parts .
Thank you...
Regards
Manoj Balakrishnan.
Part Number: REF102 Other Parts Discussed in Thread: REF5010 Hello,
Is there a newer alternative to REF102AU series voltage reference? I am looking for improved accuracy and performance.
Thank you.
Part Number: REF102 Hi,
For the Part REF102, we have ordered and received samples. Attached top marking of the IC we received. But, it doesn’t give clarity about the grade of the IC as shown in the below snip:
Kindly clarify on this.
Part Number: REF102 Hello,
I am trying to create a negative reference of -10V. I have a doubt about the FIgure 6 in the datasheet of REF102. The formula 1.4mA < (5v-IL)/Rs< 5.4mA is it right?, because you have to substract IL to 5v.
Thank you for…