Part Number: VOLT-DIVIDER-CALC It is hard to believe that a design aid as poor as "VOLT-DIVIDER-CALC" should exist on TI's otherwise excellent web site.
1) The first thing I noticed is that it often gives answers that are plain wrong. For…
Hello Foong Wei Seng,
Here you can find the accuracy of the feedback node in PFM as well as in CCM: TPS63070 datasheet | TI.com
The output accuracy is dependent on the feedback node accuracy and the resistor divider accuracy. This tool helps to calculator…
Part Number: BOOSTXL-DRV8320RS Hello, We are using the BOOSTXL-DRV8320RS and TMS320F28004x with a very small low power motor, roughly 1.8 watts. The motor voltage is 12V and draws roughly 0.15 amps @ 4000 rpm. Max motor current is 0.620 amps.
I see that…
Hi,
This means the voltage divider alone cannot get 5V - you need to get the volt-seconds clamp correct too. The voltage divider can only adjust the output voltage up to the volt-seconds allowed.
Part Number: BQ76952 Dear,
We are using BQ76952(5-volt Logic Level) and SPI flash(3.3-volt signal using voltage divider down logic level) on the same SPI bus. But getting the wrong data on Flash register read because if the BQ chip select is HIGH then…
Hello Biao,
Thank you.
You need to follow the EVM for the divider design. The 0.5V is the value at nominal 3.3V.
When the 3,3V reduces to around 3V the divider value will be 0.45V and the VMON_VSYS comparator detects the under voltage.
So bothe 0.5V and…
Part Number: TMS320F280039C Other Parts Discussed in Thread: SYSCONFIG Hi TI Team
I am trying to read AC volts through ADC on my TMS320F280039C, my AC volts input comes from output of my op-amp and i can see my sine wave and i have set 1.65 V DC offset…
Hello Bhuvaneshwari,
I used an excel-based load switch tool available at the link below to calculate the conduction losses in the FETs. This tool does not allow for paralleling FETs but you can simply divide the current by the number of parallel FETs…
Part Number: AMC3330 hi,
in sbaa553 277V is rms voltage and must be divided by 0.7 for peak voltage
therefore peak voltage will be 277/0.7 = 395 Vpeak
and then VLL is about 1.7 * 395 = 671 volt
are i'm true?
best regard
Part Number: TPS7B81 I'm using the TPS7B8133DRVR a 3.3V Linear LDO Regulator. I'd like to put a resistor divider up to IN(PIN 1) from the EN(Pin 2) pin. I'd use a 22Kohm between IN and EN pin then divide it down with a 6Kohm resistor to ground…