transfer chara of clamper
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transfer chara of clamper
Hello Poomima,
Thank you for your inquiry about TINA. Since TINA is a DesignSoft/TINA program, questions are handled by using the DesignSoft support page: http://www.tina.com/technical-support/ .
The DesignSoft/TINA team is very helpful and this is the most direct way for TINA support. Please advise by Reply when the issue has been resolved.
Regards,
~Leonard
I have shared the file. Here I have connected a negative clamper circuit and gave a sine wave as input. The expected output is a dc shifted version of the input sine wave, shifted downwards. Inorder to view the transfer characteristics (output voltage vs input voltage), I selected the Analysis -> DC analysis -> DC transfer characteristics. Instead of the expected linear and dc shifted graph, I got a dc output equal to the sum of the diode drop and bias voltage. It would be helpful if someone could find what went wrong.
Hi Poornima,
as long as the cap is present in your circuit, the only DC current path comes from the bias voltage. So the "DC transfer characteristic" TINA-TI shows is correct
Kai
In theory, the capacitor quickly charges to the maximum value of the peak voltage, for the positive half of the input & holds this charge in the negative half cycle. This output is level shifted a sine wave. How can I plot the transfer chara between the output ac and the input ac? I need to get a dc shifted linear graph.
Hi Poornima,
you could select the voltage generator as control object and step the amplitude from 0V to 5V:
By the way, for sudden changes of input voltage the circuit looks like a short circuit and an destroying current could flow through the diode. So you might want to add a small current limiting resistor?
Kai