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# INA219: Issue with the calibration register

Part Number: INA219

Hi everybody,

I am currently working on a board with an INA219BIDR. And I have an issue with the calibration register, in the datasheet we can read that : (page 12)

So I defined my maximum current at 2 Amps, and I have Rshunt= 0.002 mOhms.

My calculations are :

Current_LSB = 2 / 2^15 = 0.000 061 035 156

Cal = trunc(0.04096 / (0.000 061 035 156 * 0.002)= 335 544

But the register length is 16 bits so the max value is 65535

Did I fail somewhere ?

Thanks

Lucas

• Hello Lucas,

Thank you for using the TI forum.  The math you showed is correct, however there is a problem with your setup.  If you have a maximum current of 2A, and use only a 2mΩ shunt resistor, then your full scale current measurement takes place over 2A*2mΩ=4mV.  4mV is a very small percentage of the device measurement range, so your measured value will be very noisy.  If you use the smallest measurement range device setting at PGA = /1, then the full scale range would be ±40mV. If you adjust your shunt to ~20mΩ then you will utilize the full 40mV range, giving you a much better measurement. This would also adjust your calibration value to 33554, which will be able to fit inside the calibration register.