Other Parts Discussed in Thread: NE5534
Hi Experts,
Seeking your assistance:
I build an transimpedance amplifier circuit with the OPA2810. In a special condition, the inverting input pin is (quasi) connected to the positive supply voltage of 12V. The non-inverting input pin is connected to ground over a 2kOhm resistor (see picture of the simplified schematic).
I assumed (based on datasheet section 8.3.1 (see below)) that the differential input voltage is clamped to 7V, so the non-inverting input pin should have a potential of about 5V (=12V-7V). But the measured voltage (real measurement, no simulation) of the non-inverting input pin was only 0.44V (I_In = 235µA).
So on one hand the input currents are far less than the maximum rating but on the other hand the differential input voltage is greater than the maximum rating. Will this situation damage the chip or is it already damaged?
OPA2810 Datasheet statings:
Absolute maximum ratings:
- Differential input voltage: +-7V
- Continuous input current: +-10mA
Section 8.3.1:
“The OPA2810 also includes input clamps which enable maximum input differential voltage of upto 7 V (lower of 7 V and total supply voltage). […]
The input bias currents are also clamped to maximum 300 μA, as Figure 57 shows, which does not load the previous driver stage or require current-limiting resistors (except limiting current through the input ESD diodes when input common-mode voltages are greater than the supply voltages).
Thank you in advance for your response.
Regards,
Archie A.