hi,
in sbaa553 277V is rms voltage and must be divided by 0.7 for peak voltage
therefore peak voltage will be 277/0.7 = 395 Vpeak
and then VLL is about 1.7 * 395 = 671 volt
are i'm true?
best regard
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Hello,
The paper describes these parameters. The line-to-line voltage between the two 277V sources is 480V and is reduced to 1V through the split-tap configuration. The equation to get the line voltage is:
Best regards,
Eva