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Original question:

OPA690 Asymmetrical Power Supplies

OPA690: DIS_N pin leaks electricity to the VS+ pin

Matt Qi
Expert 3070 points
Part Number: OPA690

Hi team,

My customer faced a leakage issue in the case of OPA690IDBVR:

Currently, my customer encountered a situation where the DIS_N pin leaks electricity to the VS+ pin.

Is this an official phenomenon of TI: OPA690IDBVR?

Test method, disconnect the input power of VS+ and VS_ of OPA690IDBVR, the DIS_N pin supplies 3.3V power, but the 2.4V level can be measured on VS+.

Thanks for your time and effort.

Best Regards,

Matt.

  • 0
    TI__Expert 6050 points

    Hi Matt,

    Can you confirm one thing: is there an input signal present to the OPA690? If so, can you provide more details about the input signal (i.e. amplitude, DC signal or AC signal/frequncy, waveform type)?

    I will discuss this with the team to see if it is expected or known phenomenon in the meantime.

    Thanks,

    Nick

  • 0 in reply to Nick Nauman
    TI__Expert 3070 points

    Hi Nick,

    There is no input signal at all. Customer has just tested the leakage issue of OPA690.

    Do you have any update from your team? Customer is waiting for your support and help. 

    Thanks for your time and effort.

    Best Regards,

    Matt.

  • 0 in reply to Matt Qi
    TI__Mastermind 19286 points

    Hi Matt,

    Nick will be online to provide an answer sometime tomorrow, 3/27/24.

    Best,

    Alec

  • 0 in reply to Alec Saebeler
    TI__Expert 3070 points

    Hi Alec,

    I do not need this kind of postpone reply, just tell me what have you done and seen, and give me a first-stage conclusion.

    Customer is waiting for us.

    Best Regards,

    Matt.

  • 0 in reply to Matt Qi
    TI__Expert 6050 points

    Hi Matt,

    I apologize for the delay in my response as I was offline yesterday.

    It is suspected that you are seeing a voltage drop across the diode to the power supply. There will be no DC current flow through the diode in the way it is configured, however there will be some inherent capacitance that will charge up and hold the supply voltage pin to a potential. 

    Thanks,

    Nick