Hi, I want to know how does this circuit work, because I have an application with a battery (12V/4Ah), with a charge controller, and I don't know if I can use this. I changed resistor RH and RL with 0.1 ohm - 1w.
Thanks for all your support.
Jenny
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Hi, I want to know how does this circuit work, because I have an application with a battery (12V/4Ah), with a charge controller, and I don't know if I can use this. I changed resistor RH and RL with 0.1 ohm - 1w.
Thanks for all your support.
Jenny
Jenny,
This application circuit shows two ways to measure current in a battery, one measuring on the "high" side of the battery, one on the "low" side. You would only use one of the two circuits in a real application. The selection of which method to use (high or low side measurement) depends on your application needs.
Each of these circuits measures the voltage drop on a 10 ohm resistor with a difference amplifier configuration having a gain of 10. The lower circuit is a slightly simpler design with four resistors around the op amp to form the gain of 10 difference amplifier. This low-side measurement is easier and does not require highly accurate resistors because the common-mode voltage of the measurement is low. These two blogs provides some background:
Difference Amplifiers—the need for well-matched resistors
Making Your Own Difference Amp—sometimes 1% resistors are good enough
Regards, Bruce.