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Part Number: LM25056A
Need to measure current from 1uA to 100mA.
May I know whether LM25056A can be used for such purpose.
May I know LM25056A will be able to measure current from 1uA to 100mA with one shunt resistor.
Is it a good method to use Energy monitoring IC's for current measurement.
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In reply to Peter Iliya:
In reply to Hari T O0:
This was true until we released the INA190 current shunt monitor, which uses a different internal topology compared with our other current shunt monitors. This allows it to have an input bias current that is 3 orders of magnitude less than most analog current shunt monitors. These designs were made before the INA190 and thus they could not have known about this device. Before the INA190, instrumentation amplifiers and transimpedance amplifiers were what we suggested for measuring very small (nA to uA) currents.
Hope this clarifies your question.
Resolving/measuring a 1uV DC signal could be possible with the INA190A5 (500V/V gain; 20kHz BW), but would be tough. Aside from calibrating out the offset and needing a stable power supply, reference voltage, and input signal, you would need to filter the output as well. The input referred noise is 70nV/rtHz, so the output noise will be 500V/V*70nV/rtHz*sqrt(1.57*20kHz) = 6.2 mVrms output noise. So a 1uV input gained up to a 0.5mV output shift would be buried in the noise.
If you add a 2.5kΩ and 1uF capacitor to the output, then you can reduce this 6.2 mVrms output noise to around 360 uVrms. Note that the input filter with 500Ω and 1uF do not contribute to the output filtering. This filter would only be necessary if you input voltage signal is noisey and you need to filter out this input noise so it does not get gained up by the device.
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