Dear Sir:
I have read many textbooks on the topic of op amps and they have all fallen short of a detailed explanation of how an op amp's "input current/voltage constraint" mechanism is achieved when an op amp is in inverting amplifier configuration.
The "input current/voltage constraint" that I am referring to is the process whereby "virtual" ground is achieved at the input ports of an op amp.
I am not seeking a theoretical, mathematical explanation, which is offered in many textbooks, I am seeking a functional, circuit explanation - in terms of a step by step explanation of the process - whereby the op amp's differential input voltage is "tracked" by the rest of the op amp so that virtual ground is achieved at the input ports (the voltage at the input inverting terminal equals the voltage at the non-inverting positive terminal).
Let's say I have an inverting op amp circuit configured for a gain of 2 (RF=2K, R1=1K, and Vin = 1V DC) and the positive terminal is connected to ground, can someone explain to me "tracking process" whereby negative 2 volts is output by the push pull amplifier output stage.
My apologies for using the term "input current/voltage constraint" because different authors have mathematically expressed the term "input current constraint" and "input voltage constraint" in a manner which may be confusing to the reader, therefore, I have chosen to combine the terms for simplicity and pose a simple question that I believe everyone can understand.
I have attached a screen shot of a video that I watched to facilitate our discussion below:
If you have any questions about how this screenshot arose please go to this youtube link:
I look forward to reading a reply from a TI engineer. If the answer has to be detailed, then let's use the LM741 to facilitate the explanation.
