Hi team,
My question is with respect to table 2 of TIDU535 (http://www.ti.com/lit/ug/tidu535/tidu535.pdf). The selected photodiode reverse light current (or short circuit current) was 90uA based on an irradiance of 1mW/cm2. The datasheet (attached) specified another reverse light current (or short circuit current) of 125uA but with the condition of 1000 lux. My question is, why the author selected the 90uA short circuit current instead of the 125uA?
Another datasheet for the SFH213FA gives the same parameters but with irradiance (mw/cm2). So from a design aspect, should I use the short circuit current at 1000 lux (125uA) for SFH213 as the equivalent to the short circuit current at 1mW/cm2 (90uA) used in the TI Design?
Thank you.
