Part Number: OPA857EVM
I hope you're doing great. I just purchased the EVM for OPA857, and I am still operating in test mode.
The test results, however, do not conform to the specifications: I am setting the input DC bias as specified in the manual (Find VIN1 = OUT = OUTN = 1.83, then VIN2 to have OUT = 1.33, and make VIN DC = (VIN1 + VIN2)/2. I end up with DC ~ 2.08V, and AC ~ 240 mV.
However, when I apply this input, and an AC of VIN1-VIN2, I do not get the gain specified.
In fact, when I probe OUT and OUTN, I got only a considerable signal from OUT, and a very low signal from OUTN. Also, the signals are not differential, and the output swing is around 70 mV for an input voltage of 240 mV. The output signal from OUT maxes out ~ 150mVp-p, and the signal of OUTN maxes out @ few mV. Any thoughts?
My understanding is that the signals will be differential (at the output of the TIA when I probe them). I also expect the output swing to be ~500 mV for 3.3V supply.
Jacob Freet High Speed Amplifiers
The output of the OPA857 is pseudo differential...i.e one side (OUTN) stays fixed at 1.83V (on 3.3V supplies) and OUTP will change depending on the input current. For a photodiode that sources current it implies that OUTP will get smaller than 1.83V as the current increases and is equal to 1.83V (0V differential between OUTP and OUTN) when there is 0 input current.
In test mode, what I would do to get the correct bias voltage at Test_In is apply a DC voltage to first get OUTP = OUTN = 1.83V. On a 3.5V supply that voltage will be 5/9*3.5 = 1.94V. Once I find the voltage for 0V differential output I would then change the voltage at Test_in and measure the resulting differential output voltage..this will give you the test_in voltage to test_out current transfer function. Hope this makes sense.
Hi Samir Cherian,
Thanks for the clarification, I eventually realized that as well. After some debugging, it turned out that the evaluation board has two differences/mistakes:
- At the output of the TIA, in the resistor network preceding the transformer, the 56 ohms resistor has a 0 ohm resistor mounted instead (measured with multimeter).
- In the schematic, and at the output of the transformer, VOUTN is connected to ground through a 0 ohms resistor, and VOUTP is open circuit (to get the pseudo-differential topology). However, in the evaluation board, they are flipped (VOUTP is connected to ground). I am not sure if this affects the read out (whether I can still pick up the same AC signal from VOUTN instead). It would be great if you can provide an explanation of why this would/would not be possible.
After some measurements, I was able to get the expected signal from the output of the TIA (probing the node OUT and OUTN). However, the TIA output is clearly not getting buffered properly to the board output.
Please let me know what would you recommend doing in this case. I am constrained with time, and it would be great if there is any modification that I can do in the lab (substitute resistors, etc ...) that can make it work. My assumption is substituting the 0 ohms with 56 ohms, and flipping VOUTP and VOUTN should make it work.
In reply to Gerard Touma:
Hope this helps.
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