This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

OPA1611: how to interpret GBW from datasheet

Part Number: OPA1611

Dear Support,

the OPA1611 datasheet says that GBW is 80 MHz @ Gain =100 and is equal to 40 MHz @ Gain = 1.
Could you please explain me such a strange behavior ? Is data in the datasheet correct ?

Does GBW = 80 MHz @ Gain =100 really means I can set the gain @ 100 with an available bandwidth of 80MHz ?

That sounds really strange to me...

Thank you for your time.

Best,

Alberto

  • Sorry, I did not divide by the gain.... So my question is:

    Does GBW = 80 MHz @ Gain =100 really means I can set the gain @ 100 with an available bandwidth of 0.8 MHz ?

    In my application, OPA1611 shoudl have a (NON INVERTING) gain of 400. What bandwidth could I expect ?

    Sorry for the mix-up...

    Best,

    Alberto

  • Alberto,

    If the AOL plot vs frequency had only a single (dominant) pole, the unity-gain bandwidth and GBW would be the same and equation BW=GBW/Gain would work for ALL gains.  However, some op amps (including OPA1611) have a second pole (fp2~10MHz - see below) before zero (dB) crossing, which causes the above equation not to work for low gains.  In the case of OPA1611, for gains higher than ~10 (or >20dB  and thus frequency below 2nd pole) the equation works well and therefore for Gain of 400, BW = 80MHz/400=200kHz - this may be confirmed graphically by looking at the plot below.

  • Dear Marek,

    thank you so much! I should never trust the "single pole theorem"....

    Best,

    Alberto