按照参考设计电路：
1.将R1：R2设置成800:200 的时候，C10默认电压为1.4V 动态范围较大，最高可以到3.3V（1.4V-3.3V）低频增益特性很好。但是高频增益不足。
2.为了提高高频的增益，降低R1：R2的比值为500:500。 这时高频的增益会变好。但是C10的默认的电压会变高。为2.2V。动态范围为 2.2V-3.3V,导致动态范围比较小。 这样提高了高频响应，低频特性变差。
我的需求：
1.在我降低R1：R2比值的时候，不要提高C10的默认电平，或者说降低C10的默认点平。
2.或者在现有的电路上如何提高高频的增益
我的应用里面没有FM 没有L8 R8 CL。
C10调参为4.7uF
C12调参为4.7nF
According to the reference design circuit:
1. When R1:R2 is set to 800:200, the default voltage of C10 is 1.4V. The dynamic range of C10 is large, and the low-frequency gain characteristic of C10 can be up to 3.3V (1.4V-3.3V) is very good. But the high frequency gain is insufficient.
2. In order to improve the high frequency gain, reduce the ratio of R1:R2 to 500:500. At this point, the high-frequency gain will improve. But the default voltage of C10 will be higher. It's 2.2V. The dynamic range is 2.2V-3.3V, which results in a smaller dynamic range. This improves the high-frequency response and makes the low-frequency characteristics worse.
My needs:
1. When I reduce the ratio of R1 to R2, don't raise the default level of C10, or lower the default level of C10.
2. Or how to improve high-frequency gain on existing circuits
There is no FM in my application and no L8 R8 CL.
C10 parameter adjustment is 4.7uF
C12 parametric adjustment is 4.7nF
