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TAS6424L-Q1: TAS642x function

Part Number: TAS6424L-Q1
Other Parts Discussed in Thread: TAS6424

Hello Team,

Our customer has three questions about TAS642x-Q1 

- According to the training video of TAS6424, In order to detect short load, 20mA will flow to output load.  Does the 20mA always flow to load in order to detect short load? 

- When TAS642x detect short load, how does it stopped output current?

- How the thermal pad do we use? I wonder this thermal pad is in the center of the package top-side.

I am awaiting your reply.

Thanks,

Masayuki Uchihara

  • Uchihara-san,

    1. The DC detection circuit forces a 20mA current for detection.  If there is a short a voltage across the load cannot be generated.  If no voltage is generated, then it is considered a short.
    2. The current only flows for a short time during shorted load detection.  After this time, the current stops flowing.
    3. The exposed thermal pad, is in the center of the top side of the package. 

  • Gregg Scott said:

    Uchihara-san,

    1. The DC detection circuit forces a 20mA current for detection.  If there is a short a voltage across the load cannot be generated.  If no voltage is generated, then it is considered a short.
    2. The current only flows for a short time during shorted load detection.  After this time, the current stops flowing.
    3. The exposed thermal pad, is in the center of the top side of the package. 

    Thank you for your response. 

    For S2G, In my understanding, is it not necessary to flow 20mA to output for detection when the output shorted. Because it can automatically detect output voltage (0V).  is it correct.? 

    For  S2P,  Is it possible to detect S2P when AMP IC supply voltage is 8V and speaker output voltage 13V? How do I calculate the S2P? 

    Thanks,

    Masayuki Uchihara

    -  

  • Uchihara-san,

    For Short to Ground (S2G), 20mA is still forced as we do not know if there is a short until we test.  If we knew it was shorted, we would not need to test. 

    For short to power when the dc voltage on the speaker is higher than the PVDD is a different problem.  The body diode of the high side FET will conduct in this case.  The device does not need to be in an active state.  See this app note: