Why will inductor pullup increase output power at the resonance frequency?
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When the output is connected to a 50Ω load, if the pull-up is 50Ω resistor, the output will see a 50//50 = 25Ω load. If the pull up is an inductor, it will appear as high impedance so the load is still 50Ω. Voltage swing will be higher with a higher impedance load.