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LMX2581: Designing the PCB trace for output signal

Part Number: LMX2581


Hello,

I'm designing a Local Oscillator using LMX2581 for a first stage mixer. Our design demands the output frequency of 800 MHz to 1800 MHz.

My question is related to the layout design. Our intention is to fabricate the design in a FR4 PCB. When looking at the Figure 27. LMX2581 Layout Example in device datasheet, I can see the RFout pins are initially routed out from the device using, what seems like, ~7 mil PCB traces and then they became wider at the end. I'm guessing that the wider PCB trace corresponds to 50 ohm impedance. 

Usually 50 ohm line width is calculated for a specific frequency. In my case, the bandwidth is 1 GHz. Therefore, what frequency should I use to calculate the trace width? 

Also, when the trace width changed from high to low, wouldn't there be impedance mismatch and possible signal degradation? (I know practically maintaining the same trace width is not possible, but what is the effect)

Thank you.

  • Hi Pradeepa,

    The trace width does not change with frequency. There are many pcb trace calculator available in the web, you can do a google search to find it out.
    Unless you do a differential trace layout, it would never be possible to have 50ohm trace width matches with the footprint of the device. the impedance mismatch will cause some signal reflection, so you may not have a flat output power response . But this is only a 3G device, the reflection problem is not big at all.
  • Thank you for the answer. Sorry for being ignorant, yes the line width does not depend on the frequency.