R2 = 6, R3 = 16, ADCmax = 0xF30000, sample rate = 267
I am not sure what raw ADC value you get with a +5mV input. Is the raw value a signed number? If I put zero volts into the ADCout equation , I get 0.5 * ADCmax = 7,962,624.
This is 0x798000 hex. Is this the raw number you get with the inputs shorted together?
If I put -5mV into the equation I get ADCout = 7,904,563 = 0x789D33 hex
If I put +5mV into the equation I get ADCout = 8,020,685 = 0x7A62CD
Raw ADC at 5mV should be
ADCout = [3.5(+5mV)/(2*2.4V)] * 15925248 = 8020684.8 >>> 8020685
I don't have the system setup yet to measure these raw voltages and was just looking for confirmation that I understand the expected values for the raw ADC values.
I don't have the system setup yet to measure these raw voltages and was just looking for confirmation that I understand the expected values for the raw ADC values.