Hello,
On page 48, in section 9.31 the data sheet for the ADC3244 (and other ADCs) says,
"9.3.1 Analog Inputs
The ADC324x analog signal inputs are designed to be driven differentially. Each input pin (INP, INM) must swing symmetrically between (VCM + 0.5 V) and (VCM – 0.5 V), resulting in a 2-VPP (default) differential input swing. The input sampling circuit has a 3-dB bandwidth that extends up to 540 MHz (50-Ω source driving 50-Ω termination between INP and INM)."
So, my question is, how when INP or INM can be no greater than VCM + 0.5V and the other line be no less than VCM - 0.5V is the differential input swing 2-VPP? VCM + 0.5 - (VCM - 0.5) = 1.0 V. So where does the 2-VPP come from?
Thanks.