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ADC10080: Question with |VDDA-VDDIO|

Part Number: ADC10080

Based on document of SNAS177H-July 2003-Revised March 2013,

under both Converter Electrical Characteristics & AC Electrical Characteristics sections, Some of the test conditions are VDDA=+3.0V, VDDIO=2.5V,

but by footnotes, |VDDA-VDDIO| should not be exceed 100mV to ensure accuracy.

It seems...


  • Hi Jay,

    I have notified the ADC10080 expert regarding your question.
    He will provide a more detailed response soon.



  • Hi Jay,

    I believe that you are referencing footnote 3 on page 6 of the datasheet. Since "ensure accuracy" is vague, I don't know what accuracy is being referenced.

    What I can say with confidence is that all of the datasheet parameters (INL, DNL, SNR, etc...) were taken with VDDA = +3.0V and VDDIO = +2.5V. So, even though this 500 mV difference is not in accordance with footnote 3, these are these results that are given in the datasheet, and should be used in the same configuration.

    Best Regards,


  • Hi Dan,

    Thank you for your explanation.

    No doubt all parameters are based on VDDA=+3.0V and VDDIO=+2.5V and has provided enough information.

    It is irrelevant to have footnote since there is nothing under that condition.

    I can only assume performance will be better if the condition is matched, but I do not know where and how the improvements are.

    One more question, page 17, Figure 39. Is it 1Vp-p?

    Thank you very much.


  • Hi Jay,

    Looking at figure 39 as a single ended signal, yes, they are 1 Vpp. However, since this is a differential input, both Vin+ and Vin- are subtracted in the ADC, so the signal amplitude is doubled (2 Vpp).

    If you were using just a single-ended input, then the amplitude would need to be 2 Vpp.

    Best Regards,