Other Parts Discussed in Thread: IVC102
Hello, I'm having some confusion regarding the built-in offset that I'd like to get cleared up. I know it factors into the voltage conversion, but does it make it either of the following?
V = (Counts-Offset)*Scaling
Where
Offset = 2^12
Scaling = 4.096/((2^20-1)
OR
V = (Counts-Offset)*Scaling
Where
Offset = 2^12
Scaling = 4.096/((2^20-1-2^12)
Or are they both incorrect, and the voltage is determined by some other method?
