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ACD accuracy (TUE + SINAD)

Gokul Vardan
Prodigy 20 points


Hi,
First time I'm messing with ADC's.
I'm trying to find the usable bits of an ADC using the following article as the reference.
http://www.analogzone.com/acqt0515.pdf
What i don't understand is that how the author converted the TUE 0.1%FSR to 9.97bits(rms). Also as he mentioned in the conclusion when i use the square root of the sum of the square method for both TUE and ENOB I'm getting different value.

I would appriciate if somebody could elaborate this..

Thanks,

Gokul

  • 0
    TI__Guru 55466 points

    Hello Gokul,

    I used the following equations:

    Effective Number of Bits (ENOB) = ln(Full Scale Range/Noise)/ln(2)

    ENOB= ln(1/(percent Error))/ln(2)

    ENOB=ln(1/(0.1/100))/ln(2) = 9.965 = 9.97bits

    TUE = 100 percent * (square root((.003/100)^2+(.1/100)^2+(.003/100)^2))

    TUE = 0.1%

    Let me know if this helps,

    Thank you,

    Luis