My question concerns the SN65HVD20 RS485 transceiver. Please assume that I have a total of 32 nodes on my RS485 link. On the RS485 line side, how will the SN65HVD20 influence the RS485 link if one of the SN65HVD20 devices is powered off ?
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My question concerns the SN65HVD20 RS485 transceiver. Please assume that I have a total of 32 nodes on my RS485 link. On the RS485 line side, how will the SN65HVD20 influence the RS485 link if one of the SN65HVD20 devices is powered off ?
The data sheet shows on page 4 that the driver output current under power-off conditions depends on the common-mode voltage.
For the normal common-mode range (-7V to +12V) it can be up to 0.5mA and for the extended range (-20V to +25V) it can rise up to 1mA. Depending on how many transceivers you power off at once, you could have a significant impact on the buss.
regards,
Thomas
Hey Thomas:
I found, on page 5 of the datasheet, "Output Current with Power OFF" listed at -400uA to 500uA over -7V to 12V. But I'm a bit confused by this, so feel free to treat me like a 6-year-old.
I don't understand this. If my transceiver has no power (but is still hanging on the RS48 bus), how can my transceiver source any current at all, much less 500uA ? My goal is to understand how a de-powered SN65HVD08D will look in terms of current draw to an active transmitter on an operational RS485 link.
1) The term "output current" is misleading or simply wrong. (our fault, sorry). The main loading of a powered-down transceiver comes from the internal common-mode attenuator (R1 to R3) of both inputs, A and B.
2) From the data sheet (page 8) take the equivalent circuit diagrams for inputs A and B and convert the resistor network into a single common-mode input resistor as shown below.
3) Then divide the upper and lower common-mode limits of 12V and -7V by this single resistor value and you receive the corresponding load currents, which are flowing in and out of the transceiver bus terminals, depending on the polarity of the common-mode voltage applied. For the higher common-mode voltages of 25V and -20V you will get higher currents of course.
Hope this clarifies it. Regards, Thomas
Thanks Thomas. Excellent explanation. Thank you. You may close this item
Carl Reese