This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

TCAN1051HG: TCAN1051HG

Part Number: TCAN1051HG
Other Parts Discussed in Thread: TCAN1042HG

On the TI TCAN1051HG, pin 8 is a digital input which configures the transceiver for silent mode.  Pulling this pin low, ensures normal operation.

 

Section 9.3.5 (Floating Terminals) states that “The S terminal is also pulled down to force the device into Normal mode if the terminal floats.”

 

I have elected to add a pull-down resistor on pin 8 for due diligence.  I’m curious how to best size the pull down resistor on this pin… how much current would be flowing through it to ground?  I’m likely to use a standard 22KΩ resistor or 100KΩ 0402 pull down, but wanted to ensure that didn’t present any issue.  I can’t find any mention within the datasheet the current or power requirements of any pull-down to that pin.

 

I had a similar question on the TI TCAN1042HG; on this part pin 8 is a digital input which configures the transceiver for standby.  Pulling this pin low, ensures normal operation.

  • Hi Ryan,

    If you look at page 6, under Electrical Characteristics (7.6), there is a section called "S TERMINAL". This following data gives the voltage and current that will be seen on the the digital S pin. As for the size of the pull-down resistor, the Low-level input voltage (VIL) is 0.8 V. and the max Low-level input leakage current (IIL) it will see is 2 μA. Thus the maximum limit for an equivalent resistor is

    0.8 V / 0.000002 μA = 400 kΩ.

    Any resistance smaller than that will generate a smaller voltage than 0.8 V which will still be considered a LOW. so a 22k or 100k resistor will work.