if i caculate Rsense andRthr power consumption refer to I(INx+SENSEx) ,P(Rsense)=I2R=(2.47mA)2*562R <1/16W P(RTHR)=(2.47mA)2*1K<1/8W
It will be enough for Rsense using 0402 power consumption and Rthr using 0805
but if i caculate by 24/1k ,this will not enough for using 0805 pcb footprint.
is that true the Rsense current is 2.47mA?