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# ISO7763: Supply current on 50Mbps, Vcc1=Vcc2=3.3V condition.

Part Number: ISO7763

Hi,

My customer wants to calculate current on ISO7763 on active operation (50Mbps, Vcc1=Vcc2=3.3V). Could you please let us know how to calculate it?

My understanding is as follows:

Supply current ICC1 Max value = 8.4 + ((20.5 - 7.5)*40/(100-10)) + 7.5 = 21.7mA
Total supply current is ICC1+ICC2 = 43.4mA

Is it correct? Please let us know.

Thanks and best regards,
M.HATTORI.

• Hi Hattori-san,

Thank you for posting to E2E! ISO7763's supply currents are not characterized for 50Mbps signal transmission, so a conservative estimate can be made using the values for 100Mbps AC signal inputs.

As shown in your calculation, the value is specified for each side of the digital isolator separately, so the total current consumed by the isolator is Icc = Icc1 + Icc2. For the 100Mbps case, this would be completed as Icc = Icc1 + Icc2 = 16mA (typ.) x 2 = 32mA (typical).

Actual current varies based on the activity of each channel, switching frequencies, and operating conditions, but these numbers can provide an estimate; similar information can be found on the E2E post below about DC vs. AC Icc specs: