This thread has been locked.
If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.
Part Number: ISO7721
We have designed in the ISO7721 as a replacement alternative for Silicon Labs isolators. However, we did not manage to find any FIT related data from the online tool
A search for ISO7721, ISO7721FDWR yields no results.
We require details of the endurance test including number of samples assessed, number of test hours, failure rate, test temperature, etc,.... (ie, the usual results obtained from the online tool)
Can this be provided as soon as possible ?
We are glad that we were able to resolve this issue, and will now proceed to close this thread.
If you have further questions related to this thread, you may click "Ask a related question" below. The newly created question will be automatically linked to this question.
In reply to Dan Kisling:
Thank you for your patience. See below:
MTBF CONF LEVEL
MTBF USAGE TEMP
MTBF SAMPLE SIZE
MTBF TEST TEMP
MTBF NUM FAILS
Thank you for your reply Dan, really appreciate it.
One final confirmation in regards to your answer.
I see that it is stated "MTBF SAMPLE SIZE" to be 47098. Does it mean that in total, for this device silicon, 47098 samples were assessed at a test temperature of 125 degC for 1000 hours and there were 0 failures ? (ie , total equivalent number of test hours is 47098000 hours )
In reply to Christopher Sam Soon:
Would that not make the FIT 0.5 ? Because based on the data, there should be a FIT of 0.25 per die, and if like you mention, you cater for two dies, then the combined FIT should be 0.5, is it not ? Or is there some common mode failures that I am not aware of here (ie, packaging, isolation barrier, etc..)
Of course, 0.1 FIT is statistically insignificant, but I would like to have more insights on the thinking of TI regarding this peculiar case (ie, why 0.4 FIT instead of 0.5 FIT as per the test results)
I talked this over with our quality engineer some more. We calculate a 0.2 FIT and double it for 0.4 FIT. He said that you can use the 0.5 FIT number if you like since your math leads to 0.25 instead of 0.2. Sorry I don't have a better answer than that for you.
All content and materials on this site are provided "as is". TI and its respective suppliers and providers of content make no representations about the suitability of these materials for any purpose and disclaim all warranties and conditions with regard to these materials, including but not limited to all implied warranties and conditions of merchantability, fitness for a particular purpose, title and non-infringement of any third party intellectual property right. TI and its respective suppliers and providers of content make no representations about the suitability of these materials for any purpose and disclaim all warranties and conditions with respect to these materials. No license, either express or implied, by estoppel or otherwise, is granted by TI. Use of the information on this site may require a license from a third party, or a license from TI.
TI is a global semiconductor design and manufacturing company. Innovate with 100,000+ analog ICs andembedded processors, along with software, tools and the industry’s largest sales/support staff.